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erastova [34]
3 years ago
5

The frequency of a water wave that has a wavelength of 0.5 m and a speed of 4 m/s

Chemistry
1 answer:
Ulleksa [173]3 years ago
3 0

Answer:

f = 8 Hz

Explanation:

Given data:

Wavelength of wave = 0.5 m

Speed of wave = 4 m/s

Frequency = ?

Solution:

Formula:

f = v/λ

f = frequency

v = speed

λ = wavelength

Now we will put the values in formula.

f = v/λ

f = 4 m/s / 0.5 m

f = 8 s⁻¹

s⁻¹ = Hz

f = 8 Hz

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A chemical reaction in which bonds are created is usually associated with ________.
Nikolay [14]

A  reaction in which bonds are created is usually associated with the Release of energy.

What are the various types of bonds?

There are three sorts of bonds:

1. Electrovalent or  electrovalent bond

2.  chemical bond

3.  dative bond

Electrovalent or electrovalent bond are formed when one or more electrons are transferred from one atom to another.

Covalent bonds are formed when the atoms during a  molecule share an equal number of electrons.

A dative bond is one in which both electrons in a shared pair come from the same atom.

Now, atoms tend to stabilize once they form chemical bonds, releasing energy within the process. Energy is released because there's a higher level of stability associated with a low energy level.

Hence, a  reaction in which bonds are created is usually associated with the release of energy.

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4 0
1 year ago
Steam initially at 0.3 MPa, 2500 C is cooled at constant volume. (a) At what temperature will steam become saturated vapour? [12
AlladinOne [14]

Answer:

a. 123.9°C

b.

c.

Explanation:

Hello, I'm attaching a picture with the numerical development of this exercise.

a. Since the steam is overheated vapour, the specific volume is gotten from the corresponding table. Then, as it became a saturated vapour, we look for the interval in which the same volume of state 1 is, then we interpolate and get the temperature.

b. Now, at 80°C, since it is about a rigid tank (constant volume for every thermodynamic process), the specific volume of the mixture is 0.79645 m^3/kg as well, so the specific volume for the liquid and the vapour are taken into account to get the quality of 0.234.

c. Now,since this is an isocoric process, the heat transfer per kg of steam is computed as the difference in the internal energy, considering the initial condition (showed in a. part) and the final one computed here.

** The thermodynamic data were obtained from Cengel's thermodynamics book 7th edition.

Best regards.

5 0
3 years ago
combustion analysis of a hydrocarbon produced 33.01g CO2 and 13.51g H2O. Calculate the empirical formula for the hydrocarbon
masya89 [10]

Answer:

\rm CH_2.

Explanation:

Carbon and hydrogen are the only two elements in a hydrocarbon. When a hydrocarbon combusts completely in excess oxygen, the products would be \rm CO_2 and \rm H_2O. The \rm C and \rm H would come from the hydrocarbon, while the \rm O atoms would come from oxygen.

Look up the relative atomic mass of these three elements on a modern periodic table:

  • \rm C: 12.011.
  • \rm H: 1.008.
  • \rm O: \rm 15.999.

Calculate the molar mass of \rm CO_2 and \rm H_2O:

M(\mathrm{CO_2}) = 12.011 + 2 \times 15.999 = 44.009\; \rm g \cdot mol^{-1}.

M(\mathrm{H_2O}) = 2 \times 1.008 + 15.999 = 18.015\; \rm g \cdot mol^{-1}

Calculate the number of moles of \rm CO_2 molecules in 33.01\; \rm g of \rm CO_2\!:

\displaystyle n(\mathrm{CO_2}) = \frac{m(\mathrm{CO_2})}{M(\mathrm{CO2})} = \frac{33.01\; \rm g}{44.009\; \rm g\cdot mol^{-1}} \approx 0.7501\; \rm mol.

Similarly, calculate the number of moles of \rm H_2O molecules in 13.51\; \rm g of \rm H_2O\!:

\displaystyle n(\mathrm{H_2O}) = \frac{m(\mathrm{H_2O})}{M(\mathrm{H_2O})} = \frac{13.51\; \rm g}{18.015\; \rm g\cdot mol^{-1}} \approx 0.7499\; \rm mol.

Note that there is one carbon atom in every \rm CO_2 molecule. Approximately0.7501\; \rm mol of \rm CO_2\! molecules would correspond to the same number of \rm C atoms. That is: n(\mathrm{C}) \approx 0.7501\; \rm mol.

On the other hand, there are two hydrogen atoms in every \rm H_2O molecule. approximately 0.7499\; \rm mol of \rm H_2O molecules would correspond to twice as many \rm H\! atoms. That is: n(\mathrm{H}) \approx 2 \times 0.7499 \; \rm mol\approx 1.500\; \rm mol.

The ratio between the two is: n(\mathrm{C}): n(\mathrm{H}) \approx 1:2.

The empirical formula of a compound gives the smallest whole-number ratio between the elements. For this hydrocarbon, the empirical formula would be \rm CH_2.

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Sulfur dioxide is a main component of: photochemical smog, thermal inversion, industrial smog.
DedPeter [7]
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3 0
3 years ago
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