Answer: 13.1
Explanation:
To calculate the number of moles for given molarity, we use the equation:
.....(1)
Molarity of LiOH solution = 0.350 M
Volume of solution = 50.0 mL
Putting values in equation 1, we get:

Moles of
ion = 0.0175 moles

Moles of
ion = 0.00625 moles
The chemical equation for the reaction of LiOH with
follows:
For neutralization:
1 mole of
ion will react with 1 mole of
ion
As, 0.00625 moles of
ion react with=
moles of
ion
Moles of
left = (0.0175-0.00625) = 0.01125 moles
Concentration of 
![pOH= -log[OH^-]](https://tex.z-dn.net/?f=pOH%3D%20-log%5BOH%5E-%5D)
![pOH= -log[0.141]=0.851](https://tex.z-dn.net/?f=pOH%3D%20-log%5B0.141%5D%3D0.851)
pH +pOH = 14
pH = 14- pOH = 14 -0.851 = 13.1
Thus pH of the resulting solution is 13.1