Answer : The mass of sucrose added to water will be, 189.0 grams.
Explanation :
As we are given that 9 % solution (mass per volume) that means 9 grams of sucrose present in 100 mL volume of solution.
Total given volume of solution = 2.1 L = 2100 mL (1 L = 1000 mL)
Now we have to determine the mass of sucrose in solution.
As, 100 mL of solution contains 9 grams of sucrose
So, 2100 mL of solution contains 
grams of sucrose
Therefore, the mass of sucrose added to water will be, 189.0 grams.
Answer:
Explanation:
(a) Calculate the [CO₃²⁻] needed to precipitate the Zn²⁺
Let x = [CO₃²⁻] when Zn²⁺ starts to precipitate.
The equation for the equilibrium is
ZnCO₃(s) ⇌ Zn²⁺(aq) + CO₃²⁻(aq); Ksp = 1.0 × 10⁻¹⁰
0.010 x
![K_{sp} =\text{[Zn$^{2+}$][CO$_{3}^{2-}$]} = 0.010x = 1.0 \times 10^{-10}\\x = \dfrac{1.0 \times 10^{-10}}{0.010}\\\\\text{[CO$_{3}^{2-}$]} = x =\mathbf{1.0 \times 10^{-8}}](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%5Ctext%7B%5BZn%24%5E%7B2%2B%7D%24%5D%5BCO%24_%7B3%7D%5E%7B2-%7D%24%5D%7D%20%3D%200.010x%20%3D%201.0%20%5Ctimes%2010%5E%7B-10%7D%5C%5Cx%20%3D%20%5Cdfrac%7B1.0%20%5Ctimes%2010%5E%7B-10%7D%7D%7B0.010%7D%5C%5C%5C%5C%5Ctext%7B%5BCO%24_%7B3%7D%5E%7B2-%7D%24%5D%7D%20%3D%20x%20%3D%5Cmathbf%7B1.0%20%5Ctimes%2010%5E%7B-8%7D%7D)
The concentration of CO₃²⁻ when Zn²⁺ starts to precipitate is 1.0× 10⁻⁸ mol·L⁻¹.
2. Calculate [La³⁺] remaining in solution
La₂(CO₃)₂(s) ⇌ 2La³⁺(aq) + 3CO₃²⁻(aq)
x 1.0 × 10⁻⁸
![K_{sp} =\text{[La$^{3+}$]$^{2}$[CO$_{3}^{2-}$]$^{3}$} =4.0 \times 10^{-34}\\x^{2} \times (1.0 \times 10^{-8})^{3} = 4.0 \times 10^{-34}\\x^{2} \times 1.0 \times 10^{-24} = 4.0 \times 10^{-34}\\x^{2} = \dfrac{4.0 \times 10^{-34}}{1.0 \times 10^{-24}}= 4.0 \times 10^{-10}\\\\\text{[La$^{3+}$]} = x = \mathbf{2.0 \times 10^{-5} \textbf{ mol/L}}](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%5Ctext%7B%5BLa%24%5E%7B3%2B%7D%24%5D%24%5E%7B2%7D%24%5BCO%24_%7B3%7D%5E%7B2-%7D%24%5D%24%5E%7B3%7D%24%7D%20%3D4.0%20%5Ctimes%2010%5E%7B-34%7D%5C%5Cx%5E%7B2%7D%20%5Ctimes%20%281.0%20%5Ctimes%2010%5E%7B-8%7D%29%5E%7B3%7D%20%3D%204.0%20%5Ctimes%2010%5E%7B-34%7D%5C%5Cx%5E%7B2%7D%20%5Ctimes%201.0%20%5Ctimes%2010%5E%7B-24%7D%20%3D%204.0%20%5Ctimes%2010%5E%7B-34%7D%5C%5Cx%5E%7B2%7D%20%3D%20%5Cdfrac%7B4.0%20%5Ctimes%2010%5E%7B-34%7D%7D%7B1.0%20%5Ctimes%2010%5E%7B-24%7D%7D%3D%204.0%20%5Ctimes%2010%5E%7B-10%7D%5C%5C%5C%5C%5Ctext%7B%5BLa%24%5E%7B3%2B%7D%24%5D%7D%20%3D%20x%20%3D%20%5Cmathbf%7B2.0%20%5Ctimes%2010%5E%7B-5%7D%20%5Ctextbf%7B%20mol%2FL%7D%7D)
3. Calculate the percentage of the original concentration
J.J. Thomson :Plum Pudding Model
James Chadwick: Discovery of neutrons
John Dalton:Atoms indivisible
Ernest Rutherford:Positively charged nucleus
I hope this helps and have a great day!
Answer:
Global warming is when the earth is getting warmer and the greenhouse effect is when the earth reflects heat.
Explanation:
