Answer:
please give a chart/picture
Explanation:
Answer:
failure of a pair of homologous chromosomes to separate in meiosis I, failure of sister chromatids to separate during meiosis II, and failure of sister chromatids to separate during mitosis. Nondisjunction results in daughter cells with abnormal chromosome numbers (aneuploidy).
Explanation:
50 percent. If you make a Punnett square and put the genotypes Aa and Aa from the two heterozygous parents and combine them, you get the following results: AA, Aa, Aa, and aa. 2 of the four possible genotypes are heterozygous. 2/4=0.5. Fifty percent. Ta-da.
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