Answer:
90
Step-by-step explanation:
Evaluate x^2 + 2 x^2 + 3 x^2 + 4 x^2 where x = 3:
x^2 + 2 x^2 + 3 x^2 + 4 x^2 = 3^2 + 2×3^2 + 3×3^2 + 4×3^2
3^2 = 9:
3^2 + 2×9 + 3×3^2 + 4×3^2
3^2 = 9:
3^2 + 2×9 + 3×9 + 4×3^2
3^2 = 9:
3^2 + 2×9 + 3×9 + 4×9
3^2 = 9:
9 + 2×9 + 3×9 + 4×9
2×9 = 18:
9 + 18 + 3×9 + 4×9
3×9 = 27:
9 + 18 + 27 + 4×9
4×9 = 36:
9 + 18 + 27 + 36
| 3 |
| 3 | 6
| 2 | 7
| 1 | 8
+ | | 9
| 9 | 0:
Answer: 90
108 you don't need the distributive property.
By definition of the binomial coefficient,

so we have

as required.
Answer:
1. 7
2. 3
3. 9
Step-by-step explanation: