Answer:
Explanation:
It is a physical change .
If we start from 10 atm of pressure and - 40 celsius of temperature to 20 atm of pressure and 70 celsius of temperature , it is a change in which pressure increases and temperature also increases that means heat is added up to the gas . If we cool the gas we can retrieve its earlier pressure and temperature .
So it is a physical change . In physical change , we can retrieve the old position by simple means.
You can use the HWE (Hardy Weinberg Equilibrium) equations :
p + q = 1
p^2 + 2pq + q^2 = 1
If the allele combinations do not equal one after a while, evolution has occurred.
you build them like sandcastles.
you go to the beach, get some sand, put it all together, and
<em>B A M !</em>
Babies are made! :0
Answer: the mass of methyl alcohol (CH3OH) in the sample is 0.0641 g
Explanation:
1. <u>Preliminars</u>;
- Molar mass of CH₃ OH: 32.04 g/mol
- Molar mass of C₂H₅OH: 46.07 g/mol
- Molar mass of CO₂: 44.01 g/mol
- Molar mass equation: molar mass = mass in grams / number of moles
2. <u><em>Algebraic equation # 1: mass of sample burned in terms of each reagent.</em></u>
3. <u><em>Algebraic equation # 2: mass of carbon dioxide produced in terms of each reagent</em></u>.
a) Combustion of methyl alcohol
- 2CH₃OH(l) + 3O₂(g) → 2CO₂(g) + 4H₂O(g)
- 2 × 32.04 g CH₃OH → 2 × 44.01 g CO₂
- Mass of CO₂ produced from M grams of CH₃OH = M / 32.04 × 44.01 = 1.374 M
b) Combustion of ethyl alcohol
- C₂H₅OH(l) + 3O₂(g) → 2CO₂(g) + 3H₂O(g)
- 46.07 g CH₃OH → 2 × 44.01 g CO₂
- Mass of CO₂ produced from E grams of C₂H₅OH = E / 46.07 × 88.02 = 1.911 E
c) Mass of CO₂ (g) obtained, in terms of each reagent
- 1.374 M + 1.911 E = 0.386 ----- (2)
4) <u>System of equations</u>
- 1.374 M + 1.911 E = 0.386 ----- (2)
5) <u>Solution</u>
- From equation (1): E = 0.220 - M
- Substituting in equation (2): 1.374 M + 1.911 (0.220 - M) = 0.386
- 1.374 M + 0.4204 - 1.911 M = 0.386
- M = 0.0344 / 0.537 = 0.0641 g
Answer: the mass of methyl alcohol (CH3OH) in the sample is 0.0641 g