Identify the solute in the following: carbon dioxide dissolved in water

Energy in the amount of 420 J is added to a 35 g sample of water at a temperature of 10°C. What is the final temperature of the

Vsevolod [243]

The final temperature of the water, T2 = 38.57°C

Temperature can be defined as a measure of the degree of hotness or coldness of a physical object (body). Thus, it is measured with a thermometer and its units are degree Celsius (°C), Fahrenheit (°F) and Kelvin (°K).

A calorie refers to the amount of heat required to raise the temperature of a gram of water by one (1) degree Celsius (1°C).

Given the following data:

Quantity of energy = 420J

Mass = 35 grams

Initial temperature, T1 = 10°C

The specific heat capacity of water is 4.2 J/g°C.

To find the final temperature of the water (T2):

Mathematically, the quantity of energy (heat capacity) is given by the formula;

$Q = mcdt$

Where;

Q represents the heat capacity or quantity of heat.

M represents the mass of an object.

C represents the specific heat capacity of water.

dt represents the change in temperature.

Substituting the values into the formula, we have;

$420 = 3.5 \; * \; 4.2 \; * \; dt$

$420 = 14.7 \; * \; dt\\\\dt = \frac{420}{14.7}$

Change in temperature, dt = 28.57°C

Next, we would solve for the final temperature by using this formula;

$dt = T2 - T1$

$28.57 = T_{2} - 10\\\\T_{2} = 28.57 \; + \; 10\\\\T_{2} = 38.57$

Final temperature, T2 = 38.57°C

Therefore, the final temperature of the water, T2 is equal to 38.57°C

For more information visit: brainly.com/question/22736508

7 0

3 years ago

Tokyo, Japan is 8817.6 km from California. how many millimeters is this? answer in scientific notation.

vitfil [10]

Answer:

$d=8.817\times 10^9\ mm$

Explanation:

It is given that,

Japan is 8817.6 km from California. We need to convert this distance in millimeters.

We know the conversion from km to mm is as follows :

1 km = 1000000

To convert mm km to mm use the unitary method as follows :

8817.6 km = 8817.6 × 1000000

$d=8.817\times 10^9\ mm$

Hence, the distance between Japan and California $8.817\times 10^9\ mm$ .

7 0

3 years ago

An empty plastic bottle is sealed in a cool room and then moved to a very hot room. What can best be stated about the air pressu

mel-nik [20]

A fast moving stream of air has a lower air pressure than a slower air stream. As the stream of air moved over the top of the paper, the air pressure over the paper dropped. The air pressure underneath the paper stayed the same. The greater air pressure underneath lifted the paper strip and it rose. The idea that a moving air stream has lower air pressure than air that is not moving is called “Bernoulli’s Principle”.

The force of the moving air underneath the balloon was enough to hold it up. The weight added by the paper clip prevents the balloon from going too high. But that is only part of the story. The balloon stays inside the moving stream of air because the pressure inside is the air stream is lower than the still air around it. As the balloon moves toward the still air outside of the air stream, the higher pressure of the still air forces the balloon back into the lower pressure of the air stream. Bernoulli’s Principle at work again!

6 0

3 years ago

Read 2 more answers

Is soda homogeneous or heterogeneous?

german

Answer:

Thecinically it is both because and an un opened bottle of soda is homogeneous and an opened bottle of soda is herterogeneous. I hope this helps please reward branlist.

5 0

3 years ago

What is the specific latent heat of fusion of ice if it takes 863 kJ to convert 4.6 kg of ice into water at 0 C?

charle [14.2K]

Answer:

The correct answer is 187.7 J/Jg.

Explanation:

The formula for finding the specific heat of fusion is,

Specific heat of fusion = Q/m

Here Q is the heat energy added, signified in kJ, and m is the mass of the object in kg.

Based on the given information, the heat energy added or Q is 869 kJ and the mass of the ice is 4.6 Kg

Now putting the values in the formula we get,

Specific heat of fusion = Q/m

Specific heat of fusion = 863 kJ / 4.6 Kg = 187.7 J/Kg

5 0

3 years ago