Answer:
1,085g of water
Explanation:
If we have the value 4520kj is because the question is related to Energy and heat capacity. In this case, the law and equation that we use is the following:
Q= m*C*Δt where;
Q in the heat, in this case: 4520kj
m is the mas
Δt= is the difference between final-initial temperature (change of temperature), in this exercise we don´t have temperatura change.
In order to determine the mass, I will have the same equation but finding m
m= Q/C*Δt without m=Q/C
So: m= 4,520J/4.18J/g°C
m= 1,0813 g
Answer:
True, in as far as greater magnitude = greater power.
Answer:
Part 1: 7.42 mL; Part 2: 3Cu²⁺(aq) + 2PO₄³⁻(aq) ⟶ 2Cu₃(PO₄)₂(s)
Explanation:
Part 1. Volume of reactant
(a) Balanced chemical equation.

(b) Moles of CuCl₂

(c) Moles of Na₃PO₄
The molar ratio is 2 mmol Na₃PO₄:3 mmol CuCl₂

(d) Volume of Na₃PO₄

Part 2. Net ionic equation
(a) Molecular equation

(b) Ionic equation
You write molecular formulas for the solids, and you write the soluble ionic substances as ions.
According to the solubility rules, metal phosphates are insoluble.
6Na⁺(aq) + 2PO₄³⁻(aq) + 3Cu²⁺(aq) + 6Cl⁻(aq) ⟶ Cu₃(PO₄)₂(s) + 6Na⁺(aq) + 6Cl⁻(aq)
(c) Net ionic equation
To get the net ionic equation, you cancel the ions that appear on each side of the ionic equation.
<u>6Na⁺(aq)</u> + 2PO₄³⁻(aq) + 3Cu²⁺(aq) + <u>6Cl⁻(aq)</u> ⟶ Cu₃(PO₄)₂(s) + <u>6Na⁺(aq)</u> + <u>6Cl⁻(aq)</u>
The net ionic equation is
3Cu²⁺(aq) + 2PO₄³⁻(aq) ⟶ Cu₃(PO₄)₂(s)
Mass box C is 10+5. (So C is 15)
But if C was 30, how many times could you put B (5) into it?
30/5 = 6
You would need 6 boxes of B to make 30 grams of C.
Answer:
If we assume that there will be enough Hydrogen for the reaction to occur, then there will be 8 moles of NH
Explanation:
The balanced equation will look like this:
4N2 + 4H2 -> 8NH