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Lubov Fominskaja [6]
3 years ago
5

A rock climbing group reached the top of Mount Everest in the Himalayan mountains. Mount Everest is about 29,000 feet above sea

level and formed by the interaction of two tectonic plates. The group leader was surprised to find fossilized marine organisms on top of the mountain. Which of the following describes the geologic history of Mount Everest?
answer choices:
A: Two tectonic plates had different densities which caused the denser plate containing fossilized marine organisms to rise above the surface and form the Himalayan mountains.


B: Two tectonic plates had different densities which caused one plate to subduct into the ocean and the other one to rise causing marine organisms to fossilize on top of Mount Everest.


C: Two tectonic plates had the same density which caused one plate to subduct into a transform boundary that fossilized marine organisms before the Himalayan mountains were formed and uplifted.


D: Two tectonic plates had the same density and a collision of the plates pushed the advancing plate that contained fossilized marine organisms upward forming the Himalayan mountains and Mount Everest.
Chemistry
1 answer:
Maslowich3 years ago
7 0

Answer:

Two tectonic plates had the same density and a collision of the plates pushed the advancing plate that contained fossilized marine organisms upward forming the Himalayan mountains and Mount Everest.

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Ethanol (C2H5OH) melts a - 144 oC and boils at 78 °C. The enthalpy of fusion of ethanol is 5.02 kj/mol, and its enthalpy of vapo
Romashka [77]

<u>Answer:</u>

<u>For a:</u> The total heat required is 36621.5 J

<u>For b:</u> The total heat required is 58944.5 J

<u>Explanation:</u>

  • <u>For a:</u>

To calculate the heat required at different temperature, we use the equation:

q=mc\Delta T         .........(1)

where,

q = heat absorbed

m = mass of substance

c = specific heat capacity of substance

\Delta T = change in temperature

To calculate the amount of heat required at same temperature, we use the equation:

q=m\times \Delta H      ........(2)

where,

q = heat absorbed

m = mass of substance

\Delta H = enthalpy of the reaction

The processes involved in the given problem are:

1.)C_2H_5OH(l)(35^oC)\rightarrow C_2H_5OH(l)(78^oC)\\2.)C_2H_5OH(l)(78^oC)\rightarrow C_2H_5OH(g)(78^oC)

  • <u>For process 1:</u>

We are given:

Change in temperature remains the same.

m=42.0g\\c_l=2.3J/g.K\\T_2=78^oC\\T_1=35^oC\\\Delta T=[T_2-T_1]=[78-35]^oC=43^oC=43K

Putting values in equation 1, we get:

q_1=42.0g\times 2.3J/g.K\times 43K\\\\q_1=4153.8J

  • <u>For process 2:</u>

We are given:

Conversion factor: 1 kJ = 1000 J

Molar mass of ethanol = 46 g/mol

m=42.0g\\\Delta H_{vap}=38.56kJ/mol=\frac{35.56kJ}{1mol}\times (\frac{1000J}{1kJ})\times (\frac{1}{46g/mol})=773.04J/g

Putting values in equation 2, we get:

q_2=42.0g\times 773.04J/g\\\\q_2=32467.7J

Total heat required = [q_1+q_2]

Total heat required = [4153.8J+32467.7J]=36621.5J

Hence, the total heat required is 36621.5 J

  • <u>For b:</u>

The processes involved in the given problem are:  

1.)C_2H_5OH(s)(-155^oC)\rightarrow C_2H_5OH(s)(-144^oC)\\2.)C_2H_5OH(s)(-144^oC)\rightarrow C_2H_5OH(l)(-144^oC)\\3.)C_2H_5OH(l)(-144^oC)\rightarrow C_2H_5OH(l)(78^oC)\\4.)C_2H_5OH(l)(78^oC)\rightarrow C_2H_5OH(g)(78^oC)

  • <u>For process 1:</u>

We are given:

Change in temperature remains the same.

m=42.0g\\c_s=0.97J/g.K\\T_2=-144^oC\\T_1=-155^oC\\\Delta T=[T_2-T_1]=[-144-(-155)]^oC=11^oC=11K

Putting values in equation 1, we get:

q_1=42.0g\times 0.97J/g.K\times 11K\\\\q_1=448.14J

  • <u>For process 2:</u>

We are given:

m=42.0g\\\Delta H_{fusion}=5.02kJ/mol=\frac{5.02kJ}{1mol}\times (\frac{1000J}{1kJ})\times (\frac{1}{46g/mol})=109.13J/g

Putting values in equation 2, we get:

q_2=42.0g\times 109.13J/g\\\\q_2=4583.5J

  • <u>For process 3:</u>

We are given:

Change in temperature remains the same.

m=42.0g\\c_l=2.3J/g.K\\T_2=78^oC\\T_1=-144^oC\\\Delta T=[T_2-T_1]=[78-(-144)]^oC=222^oC=222K

Putting values in equation 1, we get:

q_3=42.0g\times 2.3J/g.K\times 222K\\\\q_3=21445.2J

  • <u>For process 4:</u>

We are given:

m=42.0g\\\Delta H_{vap}=38.56kJ/mol=\frac{38.56kJ}{1mol}\times (\frac{1000J}{1kJ})\times (\frac{1}{46g/mol})=773.04J/g

Putting values in equation 2, we get:

q_4=42.0g\times 773.04J/g\\\\q_4=32467.7J

Total heat required = [q_1+q_2+q_3+q_4]

Total heat required = [448.14+4583.5+21445.2+32467.7]J=58944.5J

Hence, the total heat required is 58944.5 J

7 0
3 years ago
What is the electron geometry if you have 4 electron groups around the center atom? What is the electron geometry if you have 4
nadya68 [22]

Answer:tetrahedral

Explanation:

According to Valence Shell Electron Pair Repulsion Theory (VSEPR). The number of electron pairs on the valence shell of the central atom in a molecule influences the shape of that molecule. Four electron pairs around the central atom of a molecule leads to a tetrahedral geometry as predicted by VSEPR.

8 0
3 years ago
5. Which type of substance yields hydrogen ions, H+, in
GaryK [48]

Answer: An Arrhenius acid is a type of substance yields hydrogen ions, H^{+}, in an aqueous solution.

Explanation:

Substances that give dissociate to give hydrogen ions or protons when dissolved in an aqueous solution are called Arrhenius acid.

For example, HCl is a strong acid and upon dissociation in water it gives the following ions.

HCl \rightarrow H^{+} + Cl^{-}

Thus, we can conclude that an Arrhenius acid is a type of substance yields hydrogen ions, H^{+}, in an aqueous solution.

7 0
3 years ago
What is the mass of 2.90 ×1022 formula units of NaOH (Molar mass = 40.0 g/mol)?
enyata [817]
<h3>Solution:</h3>

\text{mass of NaOH = 2.90 × 10²² NaOH formula units} × \frac{\text{1 mol NaOH}}{\text{6.022 × 10²³ NaOH formula units}} × \frac{\text{40.0 g NaOH}}{\text{1 mol NaOH}}

\boxed{\text{mass of NaOH = 1.926 g}}

5 0
3 years ago
Read 2 more answers
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Contact [7]

Answer:

The first and most obvious pattern I see is that all gas giants have an atmosphere mainly made up of hydrogen

The second thing I notice is that all the rocky planets have a significant amount of Nitrogen in their atmospheres except Mercury.

The third thing I notice is that all planets have one element that makes up 75% or more of its atmosphere except Mercury.

(If this is good, may I have brainliest, <em>please</em>? I'm kinda poor..)

6 0
3 years ago
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