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Lubov Fominskaja [6]
3 years ago
5

A rock climbing group reached the top of Mount Everest in the Himalayan mountains. Mount Everest is about 29,000 feet above sea

level and formed by the interaction of two tectonic plates. The group leader was surprised to find fossilized marine organisms on top of the mountain. Which of the following describes the geologic history of Mount Everest?
answer choices:
A: Two tectonic plates had different densities which caused the denser plate containing fossilized marine organisms to rise above the surface and form the Himalayan mountains.


B: Two tectonic plates had different densities which caused one plate to subduct into the ocean and the other one to rise causing marine organisms to fossilize on top of Mount Everest.


C: Two tectonic plates had the same density which caused one plate to subduct into a transform boundary that fossilized marine organisms before the Himalayan mountains were formed and uplifted.


D: Two tectonic plates had the same density and a collision of the plates pushed the advancing plate that contained fossilized marine organisms upward forming the Himalayan mountains and Mount Everest.
Chemistry
1 answer:
Maslowich3 years ago
7 0

Answer:

Two tectonic plates had the same density and a collision of the plates pushed the advancing plate that contained fossilized marine organisms upward forming the Himalayan mountains and Mount Everest.

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False

there is actually 9
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What is included in a compaarative investigation
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a scientific question

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In the spring of 1984, concern arose over the presence of ethylene dibromide, or EDB, in grains and cereals. EDB has the molecul
Lady bird [3.3K]

869.6 × 10¹⁴ molecules of EDB

Explanation:

We have 1.9 lb of flour with a EDB concentration of 31.5 ppb.

We need to transform lb in grams.

1 lb = 453.6 grams

1.9 lb = (1.9 × 453.6) / 1 = 861.8 grams

Now we determine the number of molecules of EDB in the sample by devise the following reasoning:

if we have        31.5 × 10⁻⁹ g of EDB in 1 g of sample

then we have   X  g of EDB in 861.8 g of sample

X = (31.5 × 10⁻⁹ × 861.8) / 1 = 27146.7 × 10⁻⁹ g of EDB

Molecular mass of EDB (C₂H₄Br₂) = 188 g/mole

Taking in account that 1 mole of any substance contains 6.022 × 10²³ (Avogadro’s number) molecules we devise the following reasoning:

if       188 g of EDB contains 6.022 × 10²³ molecules

then 27146.7 × 10⁻⁹ g of EDB contains Y molecules

Y = (27146.7 × 10⁻⁹ × 6.022 × 10²³) / 188 = 869.6 × 10¹⁴ molecules of EDB

Learn more:

about Avogadro’s number

brainly.com/question/1445383

#learnwithBrainly

8 0
3 years ago
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The sulfur atom of sulfur dioxide is considered to be sp2-hybridized. The expected bond angle is 120°, but is actually slightly
Alja [10]

Answer: The bonds are intermediate between double and single bonds

Explanation:

A closer look at the diagram below shows that the bonds in sulphur IV oxide are intermediate between double and single bonds. Hence they do not have the exact bond angle of single bonds. This is why the bond angle is not exactly 120°. There are two resonance structures in the diagram that clearly show this point.

6 0
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Naturally occurring indium has two isotopes, indium-113(112.9040580 amu) and Indium-115 (114.9038780 amu. The atomic mass of ind
Kruka [31]

Answer:

The answer to your question is: letter c (96%)

Explanation:

Indium -113 (112-9040580 amu) ₁₁₃In

Indium-115 (114.9038780 amu)  ₁₁₅In

Atomic mass of Indium is 114.82 amu ₁₁₄.₈₂In

Formula

Atomic mass = m₁(%₁) +m₂(%₂)  / 100

%₁ = x I established this is an equation

%₂ = 100 - x

Substituting values

114.82 = 112.8040x + 114.9039(100-x) /100    and know we expand and simplify

114.82 = 112.8040x + 11490.39 - 114.9039x  /100

11482 = 112.8040x -114.9039x +11490.39

11482 - 11490.39 = 112.8040x -114.9039x

-8.39 = -2.099x

x = 3.99

Then % of Indium-115 = 100 - 3.99 = 96

5 0
3 years ago
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