Answer:
it's c because it's the missing value
Answer:
X=11
Step-by-step explanation:
Answer:
4x^3+4x^2
Step-by-step explanation:
f(x) = 4x^2
g(x) = x+1
(f•g)(x) = (4x^2) *(x+1) = 4x^3+4x^2
Answer:
1) you're going to have to flip the coins (or fake numbers) for the experimental trials.
2) for the theoretical, there is 1/2 chance for heads or tails with each toss, so you'd expect that out of 10 tosses, 5 heads, 5 tails. out of 100 tosses- 50 heads, 50 tails.
When tossing 2 coins- 1/2×1/2 = 1/4 (25%) chance that 2 heads, 2 tails, or 1 heads & 1 tails. Deviation value comes from after you done your flipping and recorded your data. So if on 100 flips you actually got 50 and 50 (rarely us that exact ;), the deviation from the expected of 50/50 would be 0.00. If however you flipped 100 heads or 100 tails (impossible), then the deviation value would be 1.00.
|(100-50)| ÷ 50 = 50÷50 = 1.00
So usually you may have data like: 47/53 or something a little off than 50/50, making deviation |(47-50)| ÷ 50 = 3÷50 = 0.06.
Now the number of flips is important for the outcome! So if a coin toss if 10 times had 4 heads, 6 tails, the deviation value would be:
|(4-5)| ÷ 5 = 1÷5 = 0.20
So increasing the # flips DECREASES the deviation value!!
Whether it's from 10 to 100, or from 100 to 200. Look at my example of how the 10-flip deviation of 0.20 decreased to 0.06 with 100-flip
<h2>
<em>Answers</em><em>:</em></h2>
<em>A</em><em>.</em><em> </em><em> </em><em>1</em><em>6</em><em>/</em><em>4</em><em>9</em>
<em>B</em><em>.</em><em> </em><em> </em><em> </em><em> </em><em>2</em><em> </em><em>1</em><em>/</em><em>1</em><em>0</em>
<em>pl</em><em>ease</em><em> see</em><em> the</em><em> attached</em><em> picture</em><em> for</em><em> full</em><em> solution</em>
<em>hope</em><em> it</em><em> </em><em>helps</em>
<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>
