Answer:
Van der waal's force of attraction
Explanation:
Van der waal's force of attraction
Forces of Van der Waals involve attraction and repulsion among atoms, particles, and surfaces as well as many other intermolecular forces. These vary from covalent and ionic bonding in that they are caused by similarities in surrounding particle fluctuating polarizations (a result of quantum dynamics).
Answer : The cell potential for this reaction is 0.50 V
Explanation :
The given cell reactions is:

The half-cell reactions are:
Oxidation half reaction (anode): 
Reduction half reaction (cathode): 
First we have to calculate the cell potential for this reaction.
Using Nernest equation :
![E_{cell}=E^o_{cell}-\frac{2.303RT}{nF}\log \frac{[Zn^{2+}]}{[Pb^{2+}]}](https://tex.z-dn.net/?f=E_%7Bcell%7D%3DE%5Eo_%7Bcell%7D-%5Cfrac%7B2.303RT%7D%7BnF%7D%5Clog%20%5Cfrac%7B%5BZn%5E%7B2%2B%7D%5D%7D%7B%5BPb%5E%7B2%2B%7D%5D%7D)
where,
F = Faraday constant = 96500 C
R = gas constant = 8.314 J/mol.K
T = room temperature = 
n = number of electrons in oxidation-reduction reaction = 2
= standard electrode potential of the cell = +0.63 V
= cell potential for the reaction = ?
= 3.5 M
= 
Now put all the given values in the above equation, we get:


Therefore, the cell potential for this reaction is 0.50 V
Answer:It has the lowest effective nuclear charge of the four new elements.
Rris is how u right it Mg=? Because it ask u a question and then you put the equal sign and then you put the question mark because you don't know it yet