C' ( 0, 3)
A' ( 2 , 1)
C'A' = CA
C'A' = √(2^2 + 2^2) = √8 = 2√2
C'A' = CA = 2√2
Plug it into the distance formula.
d= (sqrt) (x2-x1)^2 +(y2-y1)^2
d= (sqrt) (17-17)^2 + (33-(-21)^2
d=(sqrt) (0)^2 + (33 +21)^2
d= (sqrt) (54)^2
d= (sqrt) 2916
d=54
The distance is 54 units.
I hope this helps!
~kaikers
Answer:
area of path is area of park with path - area of rectangular park
area of park =l x b= 45 x 30=1350 cm2
area of park with path is =45+2.5+2.5 x 30+2.5+2.5 = 1750cm2
area of path = 1750-1350=400 cm2
Step-by-step explanation:
Answer:
n + 7/5
Step-by-step explanation:
<u>Solve</u>
Let "n" be the varable.
Add 7 = +
Then, Divideby 5 = ÷
Therefore, the equation for this is n + 7 ÷ 5
