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3 years ago

I NEED HELP ASAP PLS

Mathematics

2 answers:

Salsk061 [2.6K]3 years ago

7 0

Answer:

d) all notebooks would fall at the same time

Step-by-step explanation:

One thing you learn in Physics class is that acceleration due to gravity is the same for all objects: their change in speed as a function of time is not dependent upon their weight.

For similar objects (notebooks) falling from desk-top height, the effect of air resistance is probably negligible, and is unlikely to be measurable in a casual experiment of the sort described here.

_____

If you assume heavier objects fall faster, then answer selections b and c both would have to be correct. If you assume there is only one correct answer, it must be d.

Eva8 [605]3 years ago

6 0

Answer:

e) 2.5

Step-by-step explanation:

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Solve for x: x^2-2x=15

Lyrx [107]

Answer:

Step-by-step explanation:

x^2 - 2x = 15

x^2 - 2x - 15 = 15 - 15 (Subtract 15 from both sides.)

x^2 - 2x -15 = 0 (Simplify.)

<em />

<em>Set up & solve for a quadratic formula</em>

<h3><em>* I will solve for your first x</em></h3>

2 + root 64 / 2x 1 = 2 + root 64 / 2

root 64 = 8

= 2 + 8 / 2

= 10 / 2

= 5

<em>To solve for the second, follow the same pattern/formula for the first that I used to get 5.</em>

5 0

3 years ago

Did I get this first question right?

vivado [14]

Answer:

Step-by-step explanation:

the correct answer is 56.55 inches

3 0

3 years ago

Read 2 more answers

PLEASE HELP !!!

Wewaii [24]

Answer:

Step-by-step explanation:

its quadratic because it has the almost oval-ish shape

3 0

3 years ago

C) Find the point of trisection of the line segment AB, where A<br> (-6, 11) and B (10, -3).

PtichkaEL [24]

Answer:

Step-by-step explanation:

Δx = 10-(-6) = 16

Δy = -3-11 = -14

(-6+16/3, 11-14/3) = (-⅔, 6⅓)

(10-16/3, -3+14/3) = (4⅔, 1⅔)

6 0

3 years ago

You operate a gaming Web site, www.mudbeast.net, where users must pay a small fee to log on. When you charged $3 the demand was

Doss [256]

Answer:

A) The linear relation between price and demand is:

$d=-550x+2750$

The revenue R is:

$R=-550x^2+2750x$

B) The profit functionP is:

$P=-550x^2+2750x-30$

C) The largest monthly profit is obtained with a log-on fee of $2.5 per month. This corresponds to a profit of $3407.5.

Step-by-step explanation:

We have a site where the number of log-ons depends on our monthly fee. A linear relation is established between the price (log-on fee) and the number of log-ons.

We have two points for this linear relationship:

At price x=3, the demand is d=1100.
At price x=2.5, the demand is d=1375.

We will model the relation:

$d=mx+b$

We can calculate the slope m as:

$m=\dfrac{\Delta d}{\Delta x}=\dfrac{d_2-d_1}{x_2-x_1}=\dfrac{1375-1100}{2.5-3}\\\\\\m=\dfrac{275}{-0.5}=-550$

Then, replacing one point in the linear equation, we can calculate the intercept b:

$d_1=mx_1+b\\\\1100=(-550)\cdot 3+b\\\\1100=-1650+b\\\\b=1100+1650=2750$

Then, the linear relation between demand and price is:

$d=-550x+2750$

The revenue R can be expressed as the multiplication of the price and the demand:

$R=x\cdot d=x(-550x+2750)=-550x^2+2750x$

If we have a fixed cost of $30 per month, the profit P is:

$P=R-FC=-550x^2+2750x-30$

We can maximize the profit by deriving the profit function and making it equal to zero.

$\dfrac{dP}{dx}=0\\\\\\\dfrac{dP}{dx}=-550(2x)+2750(1)=0\\\\\\-1100x+2750=0\\\\x=\dfrac{2750}{1100}=2.5$

This corresponds to a profit of:

$P(2.5)=-550(2.5)^2+2750(2.5)-30\\\\P(2.5)=-550\cdot 6.25+6875-30\\\\P(2.5)=-3437.5+6875-30\\\\P(2.5)=3407.5$

5 0

3 years ago