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Debora [2.8K]
3 years ago
9

Physical Science

Physics
1 answer:
Kobotan [32]3 years ago
5 0

Answer:

Net force = 7.10 N

Direction of the resultant force = 45° from the horizontal in South-west direction

Explanation:

Forces acting on opposite directions horizontally are 10N and 5N.

Resultant force horizontally F(1) = 10 - 5 = 5N (in the direction of 10 N)

Forces acting on opposite directions vertically are 7N and 2N.

Resultant force vertically F(2) = 7 - 2 = 5N (in the direction of 7N)

Now resultant force of F(1) and F(2),

F = \sqrt{(F_1)^2+(F_2)^2}

F = \sqrt{5^2+5^2}

F = 5\sqrt{2} ≈ 7.10 N

From the triangle OBC,

tanθ = \frac{\text{BC}}{\text{OB}}

tanθ = \frac{1}{1}

θ = 45°

Therefore, magnitude of the resultant force = 7.10N

Direction of the resultant force = 45° from the horizontal in south west direction.

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