Answer:
Net force = 7.10 N
Direction of the resultant force = 45° from the horizontal in South-west direction
Explanation:
Forces acting on opposite directions horizontally are 10N and 5N.
Resultant force horizontally F(1) = 10 - 5 = 5N (in the direction of 10 N)
Forces acting on opposite directions vertically are 7N and 2N.
Resultant force vertically F(2) = 7 - 2 = 5N (in the direction of 7N)
Now resultant force of F(1) and F(2),
F = 
F = 
F =
≈ 7.10 N
From the triangle OBC,
tanθ = 
tanθ =
θ = 45°
Therefore, magnitude of the resultant force = 7.10N
Direction of the resultant force = 45° from the horizontal in south west direction.