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3 years ago

Physical Science

Physics

1 answer:

Kobotan [32]3 years ago

5 0

Answer:

Net force = 7.10 N

Direction of the resultant force = 45° from the horizontal in South-west direction

Explanation:

Forces acting on opposite directions horizontally are 10N and 5N.

Resultant force horizontally F(1) = 10 - 5 = 5N (in the direction of 10 N)

Forces acting on opposite directions vertically are 7N and 2N.

Resultant force vertically F(2) = 7 - 2 = 5N (in the direction of 7N)

Now resultant force of F(1) and F(2),

F = $\sqrt{(F_1)^2+(F_2)^2}$

F = $\sqrt{5^2+5^2}$

F = $5\sqrt{2}$ ≈ 7.10 N

From the triangle OBC,

tanθ = $\frac{\text{BC}}{\text{OB}}$

tanθ = $\frac{1}{1}$

θ = 45°

Therefore, magnitude of the resultant force = 7.10N

Direction of the resultant force = 45° from the horizontal in south west direction.

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