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3 years ago

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The concentration of the mixture obtained by mixing two solutions, A and B, is 6 2/3 %. The concentration of the second mixture

obtained by mixing the same two solutions is 16.7%. Find the concentration of each of the solutions A and B, if the first mixture is obtained by mixing them in 2:7 ratio and the second is obtained by mixing them in 7:3 ratio.

1 answer:

Nuetrik [128]3 years ago

8 0

Answer:

Concentration of solution A = 23%

and concentration of solution B = 2%

Step-by-step explanation:

Lets get started

lets say that we concentration of solution A be x% and concentration of second solution be y%

we also know that first mixture is obtained by mixing them in ratio of 2:7

so linear equation representing this situation can be written as:

2(x%)+7(y%)= 9(6.66%)

changing percentage to decimal we get,

.02x+.07y=9(.0666)

.02x+.07y = 0.6 (equation 1 )

similarly , second mixture is obtained by mixing them in ratio of 7:3

so linear equation can be written as:

7(x%)+3(y%) = 10(16.7%)

.07x +.03y = 1.67 (equation 2)

solving equations 1 and 2 we get

x = 23 and y = 2

so concentration of solution A = 23%

and concentration of solution B = 2%

That's the final answer

Hope it was helpful !!

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Step-by-step explanation:

Lets solve all the expressions to match the results.

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