A store sells shirts at three prices only: $25, $30, and $35. How many different combinations are possible for the store to sell

Question

asambeis [7]

3 years ago

15

A store sells shirts at three prices only: $25, $30, and $35. How many different combinations are possible for the store to sell

20 shirts for a total of $600?

Mathematics

1 answer:

Dvinal [7] · Answer 1 · 2022-03-15T15:09:19+03:00

Answer:

11

Step-by-step explanation:

The average price of the 20 shirts is 600/20 = $30 each. So, we know that we can sell 20 shirts for $30 each to reach the goal.

For each $25 shirt we sell, we must also sell a $35 shirt to make the average price of the sale be $30 per shirt. That is any or all of the 10 pairs of $30 shirts can be replaced by a ($25, $35) pair. So, there are 10 additional ways to reach the goal.

The total number of possible combinations of shirt sales is 1 +10 = 11.