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asambeis [7]
3 years ago
15

A store sells shirts at three prices only: $25, $30, and $35. How many different combinations are possible for the store to sell

20 shirts for a total of $600?
Mathematics
1 answer:
Dvinal [7]3 years ago
5 0

Answer:

  11

Step-by-step explanation:

The average price of the 20 shirts is 600/20 = $30 each. So, we know that we can sell 20 shirts for $30 each to reach the goal.

For each $25 shirt we sell, we must also sell a $35 shirt to make the average price of the sale be $30 per shirt. That is any or all of the 10 pairs of $30 shirts can be replaced by a ($25, $35) pair. So, there are 10 additional ways to reach the goal.

The total number of possible combinations of shirt sales is 1 +10 = 11.

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Which of the following topics would lend itself only to a formal style of writing?
suter [353]
D because its more formal then the other ones.
3 0
4 years ago
Sophia did push-ups every day for 7 days. Each day after the first day, she did 5 more push-ups than the day before. In total sh
Dafna1 [17]

Answer:

Push- ups on last day = 40

Step-by-step explanation:

According to given conditions:

Let push-ups on:

1st day = x

2nd day = x + 5

3rd day = x + 10

4th day = x + 15

5th day = x + 20

6th day = x + 25

7th day = x + 30

Now total push ups = adding all

x + x + 5 + x + 10 + x + 15 + x + 20 + x+ 25 + 30 + x = 175

By adding same terms:

7x + 105 = 175

Subtracting 105 from both sides

7x + 105 - 105 = 175 - 105

7x = 70

Dividing both sides by 7 we get:

x = 70/7

x = 10

Now calculating push-ups on days:

1st day = x = 10

2nd day = x + 5 = 10 + 5 = 15

3rd day = x + 10 = 10 + 10 = 20

4th day = x + 15 = 10 + 15 = 25

5th day = x + 20 = 10 + 20 = 30

6th day = x + 25 = 10 + 25 = 35

7th day = x + 30 = 10 + 30 = 40

So number of push-ups on 7th (last) day is 40.

I hope it will help you!

8 0
3 years ago
A submarine lies 3 kilometers from the path of a target ship. The sub’s torpedoes have a range of 5 kilometers. For what distanc
aev [14]

The distance along the path of the ship be within the range of the torpedoes is 4 kilometers.

Explanation:

The submarine lies 3 km from the target ship.

Let B denotes the target ship and C denotes the submarine.

Let AC denotes the the target ship would be within the range of the torpedoes.

The image attached below illustrates that the distance between submarine and the target ship and the range of the torpedoes.

Let BC denotes the distance between the target ship and the submarine. Let AC denotes the range of the torpedoes.

To determine the length of AB, let us use Pythagorean theorem,

AC^{2} =AB^{2} +BC^{2}

Substituting the values of BC = 3 and AC = 5, we have,

5^{2} =AB^{2} +3^{2}

Squaring the terms, we get,

25 =AB^{2} +9

Subtracting both sides by 9, we have,

16 =AB^{2}

Taking square root on both sides,

AB = 4

Thus, the distance along the path of the ship be within the range of the torpedoes is 4 kilometers.

5 0
4 years ago
Anyone wanna help???
OLEGan [10]

Answer:

its probably the first 1

8 0
3 years ago
Read 2 more answers
HELP ASAP!! WILL GIVE BRAINLIEST!! ANSWER ALL PLEASE!!
agasfer [191]

Answer:

B) and A)

Step-by-step explanation:

6 0
3 years ago
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