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asambeis [7]
3 years ago
15

A store sells shirts at three prices only: $25, $30, and $35. How many different combinations are possible for the store to sell

20 shirts for a total of $600?
Mathematics
1 answer:
Dvinal [7]3 years ago
5 0

Answer:

  11

Step-by-step explanation:

The average price of the 20 shirts is 600/20 = $30 each. So, we know that we can sell 20 shirts for $30 each to reach the goal.

For each $25 shirt we sell, we must also sell a $35 shirt to make the average price of the sale be $30 per shirt. That is any or all of the 10 pairs of $30 shirts can be replaced by a ($25, $35) pair. So, there are 10 additional ways to reach the goal.

The total number of possible combinations of shirt sales is 1 +10 = 11.

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3 years ago
You have 1200 feet of fencing and you want to make two fenced in enclosures by splitting one enclosure in
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Let x = length and y = width

You would have 2 lengths, so 2x and 3 widths, so 3y

Those need to equal total length of fence:

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The 3 widths would equal total fence minus the 2 lengths:

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Solve for y: y = 400 -2/3x

Area = length x width = xy. Replace y :

Area = x(400-2/3x) = 400x-2/3x^2

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3 years ago
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Tasya [4]

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3 0
4 years ago
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Talja [164]
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7 0
3 years ago
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