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lukranit [14]
3 years ago
15

Balance these 2 equations AND identify the products and the reactants:

Chemistry
1 answer:
iogann1982 [59]3 years ago
6 0

Answer:

Explanation:

1) NaCl → Na + Cl₂

2) Na + HCl  → NaCl + H₂

Chemical equation:

NaCl → Na + Cl₂

Balanced chemical equation:

2NaCl → 2Na + Cl₂

There are two moles of sodium and two mole of chlorine on both side of equation so given chemical equation is correctly balanced and follow the law of conservation of mass.

2)

Chemical equation:

Na + HCl  → NaCl + H₂

Balanced chemical equation:

2Na + 2HCl  → 2NaCl + H₂

There are two moles of sodium and two mole of chlorine and hydrogen on both side of equation so given chemical equation is correctly balanced and follow the law of conservation of mass.

Law of conservation mass

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

Explanation:

This law was given by french chemist  Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

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A

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A chemical change is when a new substance is created, which often has its own chemical properties, so A is the correct answer.

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120 extracted from the gas

Explanation:

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52° 31' 12.0288"N and 13° 24' 17.8344" E.<br> What continent is it on?
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Why does surface area of a reactant influence the rate of the reaction?
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7 0
3 years ago
If 10.0 grams of NaHCO3 is added to 10.0 g of HCl, determine the efficiency of baking soda as an antacid if 6.73 g of NaCl was p
Lapatulllka [165]

Answer:

percentage yield of NaCl = 96.64%

Explanation:

The reaction was between NaHCO3 and HCl .The chemical equation can be represented below:

NaHCO3 + HCl → NaCl + H2O + CO2 . The balance equation is

NaHCO3 + HCl → NaCl + H2O + CO2

The question ask us to calculate the percentage yield of NaCl.

The efficiency of NaHCO3 as an antacid , the limiting reactant is NaHCO3

as

1 mole of NaHCO3 produces 1 mole of NaCl

Therefore,

molar mass of NaHCO3 = 23 +1 + 12 + 48 = 84 g

molar mass of NaCl = 23 + 35.5 = 58.5 g

1 mole of NaHCO3 = 84 g

1 mole of NaCl  = 58.5 g

since 84 g of NaHCO3 produces 58.5 g of NaCl

10 g of NaHCO3 will produce ? grams of NaCl

cross multiply

Theoretical yield of NaCl = (10 × 58.5)/84

Theoretical yield of NaCl = 585/84

Theoretical yield of NaCl  = 6.9642857143 g

percentage yield of NaCl = actual yield/theoretical yield × 100

percentage yield of NaCl = 6.73/6.9642857143 × 100

percentage yield of NaCl = 673/6.9642857143

percentage yield of NaCl = 96.635897436%

percentage yield of NaCl = 96.64%

3 0
3 years ago
Read 2 more answers
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