Glucose is a monosaccharide
First, we need to find out how many moles we have of
![Cu ( NO_{3} )_{2}](https://tex.z-dn.net/?f=Cu%20%28%20NO_%7B3%7D%20%29_%7B2%7D%20)
if we are given 6.35g.
We need to calculate the molar mass of the molecule:
Cu: 63.546g
N: 14.01g * 2 = 28.02g
O: 15.999g * 6 = 95.994
Add them together to get: 187.56g
So now we need to find the number of moles we are given. This can be done by setting up a multiplication equation and cancelling the units:
![\frac{1mole}{187.56g}* \frac{6.35g}{1}=0.034 mol _{Cu( NO_{3} )_{2} }](https://tex.z-dn.net/?f=%20%5Cfrac%7B1mole%7D%7B187.56g%7D%2A%20%5Cfrac%7B6.35g%7D%7B1%7D%3D0.034%20mol%20_%7BCu%28%20NO_%7B3%7D%20%29_%7B2%7D%20%20%20%7D)
So now that we know the number of moles that we have, we can use the molarity equation to find the volume of the solution. The molarity equation is:
![Molarity= \frac{moles}{Liters}](https://tex.z-dn.net/?f=Molarity%3D%20%5Cfrac%7Bmoles%7D%7BLiters%7D%20)
So since we are given the molarity in the equation (0.750 M), we can plug in the molarity and moles to find the volume of the solution:
![0.750= \frac{0.034mol}{volume(L)}](https://tex.z-dn.net/?f=0.750%3D%20%5Cfrac%7B0.034mol%7D%7Bvolume%28L%29%7D%20)
![volume(L)=0.04533L](https://tex.z-dn.net/?f=volume%28L%29%3D0.04533L)
So now we know that the volume is 0.04533 Liters; however the question asks for the answer in milliliters. To do this, we must multiply by 1000:
![\frac{0.045L}{1} * \frac{1000mL}{1L}=45.33mL](https://tex.z-dn.net/?f=%20%5Cfrac%7B0.045L%7D%7B1%7D%20%2A%20%5Cfrac%7B1000mL%7D%7B1L%7D%3D45.33mL%20)
So
the volume of the solution (<em>
in mL</em>
) is 45.33 mL.
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