Method 1.
Look at the picture 1.
We have:
Picture 2.
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Method 2. (Picture 3)
ΔLOM and ΔMON are isosceles triangles. Therefore the two angles opposite the legs are equal.
The sum of the internal angles in each triangle is 180°. Thereofre in ΔLMN we have:
Half of 57 is 28.5. Hoped I helped. :)
This a pretty typical right triangle trig problem; the first step is to figure out what we have and what we want in relation to an acute angle in the problem.
Here we have a right triangle, G=90°, and we're given angle F=23°. So we have to name everything in relation to F.
31 = FG is <em>adjacent </em>to F.
x = GE is <em>opposite </em>to F.
OK, we have an opposite and adjacent; that tells us we need to use the tangent of F. Let's write it:
tan 23° = tan F = opp/adj = x/31
Solving,
x = 31 tan 23°
I hate the calculator part. I used to love that part.
x = 31 tan 23° ≈ 13.16 feet
Answer: 4) x ≈ 13.2 ft
The answer is
graph A
Hope this helps :)
