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Dmitry [639]
3 years ago
11

Alexandra is attempting to drag her 32.6 kg golden retriever across the wooden floor by applying a horizontal force. What force

must she apply to move the dog with a constant speed of 0.95 m/s? The coefficient of friction between the dog and the floor is 0.72
Physics
1 answer:
vichka [17]3 years ago
7 0

Answer:

230.26 N

Explanation:

Since the speed is constant, acceleration is zero hence the net force will be given by the product of mass, coefficient of friction and acceleration due to gravity

F=0.72*32.6*9.81=230.26 N

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6.) What is
Feliz [49]

Answer:

100 V

Explanation:

Hi there!

Ohm's law states that V=IR where V is the voltage, I is the current and R is the resistance.

Plug the given information into Ohm's law (R=50, I=A)

V=IR\\V=(2)(50)\\V=100

Therefore, the voltage across this current is 100 V.

I hope this helps!

6 0
2 years ago
The tent meteorite, found in 1897 near cape York, on the west coast of Greenland, is the largest meteorite exhibited by any muse
sweet-ann [11.9K]
Answer:
3.0883 x 10^10mg

Explanation:
1 kilogram = 1000 000 milligrams
So, 30 883 x 1000 000 = 30 883 000 000mg
6 0
3 years ago
The maximum force that a grocery bag can withstand without ripping is 250 n. Suppose that the bag is filled with 20 kg of grocer
zhannawk [14.2K]

Answer:

Groceries stay in the bag.

Explanation:

Given:

Maximum force = 250 N

Bag filled with = 20 kg

Lifted acceleration = 5.0\ m/s^2

Solution:

We need to calculate the exerted force on the grocery bag by using Newton's second law.

F = ma

Where:

F = Exerted force on the object.

m = Mass of the object in kg

a = Acceleration of the object in m/s^2

Now, we substitute m = 20 kg and a = 5.0\ m/s^2 in Newton's second law,

F = 20\times 5.0

F = 100\ m/s^2

Since, the exerted force on the bag is less than 250 N, the groceries will stay in the bag.

3 0
3 years ago
The Doppler effect is an effect produced by a moving source of sound or electromagnetic waves due to the relative motion of a so
xxMikexx [17]
B. The waves would shorten as the vehicle got closer
4 0
3 years ago
Read 2 more answers
The resistance created by waves on a 120-m-long ship is tested in a channel using a model that is 4 m long Y Part A If the ship
DanielleElmas [232]

Answer:

V_m = 12.78 km/hr

Explanation:

given,

length of the ship = 120 m

length of model of the ship = 4 m

Speed at which the ship travels = 70 km/h

speed of model = ?

by using froude's law

  F_r = \dfrac{V}{\sqrt{L g}}

for dynamic similarities

  (\dfrac{V}{\sqrt{L g}})_P = (\dfrac{V}{\sqrt{L g}})_{model}

  (\dfrac{V_p}{\sqrt{L_p}}) = (\dfrac{V_m}{\sqrt{L_m}})

  (\dfrac{70}{\sqrt{120}}) = (\dfrac{V_m}{\sqrt{4}})

          V_m = 12.78 km/hr

hence, the velocity of model will be 12.78 km/h

6 0
3 years ago
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