Answer:7 cm/s
Explanation:
Given
Particle move along curve 

As it reaches the (2,3) its y coordinate is increasing at 14 cm/s
Differentiating y w.r.t time
 
 
Now at (2,3)
 
 

 
 
 
        
             
        
        
        
Answer:
The transverse component of acceleration is 26.32  where as radial the component of acceleration is 8.77
 where as radial the component of acceleration is 8.77 
Explanation:
As per the given data
u=π/4 rad
ω=u'=2 rad/s
α=u''=4 rad/s

So the transverse component of acceleration are given as 

Here


So 

The transverse component of acceleration is 26.32 
The radial component is given as 

Here 

So 

The radial component of acceleration is 8.77 
 
        
             
        
        
        
Answer:
the average force 11226 N  
Explanation:
Let's analyze the problem we are asked for the average force, during the crash, we can find this from the impulse-momentum equation, but this equation needs the speeds and times of the crash that we could look for by kinematics.
 Let's start looking for the stack speeds, it has a free fall, from rest  (Vo=0)
              
            Vf² = Vo² - 2gY
             Vf² = 0 - 2 9.8 7.69 = 150.7
             Vf = 12.3 m / s
This is the speed that the battery likes when it touches the beam.  They also give us the distance it travels before stopping, let's calculate the time
           
             Vf = Vo - g t
              0 = Vo - g t
              t = Vo / g
              t = 12.3 / 9.8
              t = 1.26 s
This is the time to stop
Now let's use the equation that relates the impulse to the amount of movement
                  I = Δp
                 F t = pf-po
The amount of final movement is zero because the system stops
                 F = - po / t
                 F = - mv / t
                 F = - 1150 12.3 / 1.26
                 F = -11226 N
This is the average force exerted by the stack on the vean
 
        
             
        
        
        
I was about to say:  because people generally get comfortable with 
what they think they know, and don't like the discomfort of being told 
that they have to change something they're comfortable with.
But then I thought about it a little bit more, and I have a different answer.
"Society" might initially reject a new scientific theory, because 'society'
is totally unequipped to render judgement of any kind regarding any
development in Science.  
First of all, 'Society' is a thing that's made of a bunch of people, so it's 
inherently unequipped to deal with scientific news.  Anything that 'Society' 
decides has a lot of the mob psychology in it, and a public opinion poll or 
a popularity contest are terrible ways to evaluate a scientific discovery.
Second, let's face it.  The main ingredient that comprises 'Society' ... people ...
are generally uneducated, unknowledgeable, unqualified, and clueless in the 
substance, the history, and the methods of scientific inquiry and reporting.
There may be very good reasons that some particular a new scientific theory 
should be rejected, or at least seriously questioned.  But believe me, 'Society'
doesn't have them. 
That's pretty much why.
  
        
             
        
        
        
Answer:

Explanation:
For this case  we can use the second law of Newton given by:

The friction force on this case is defined as :

Where N represent the normal force,  the kinetic friction coeffient and a the acceleration.
 the kinetic friction coeffient and a the acceleration. 
For this case we can assume that the only force is the friction force and we have:

Replacing the friction force we got:

We can cancel the mass and we have:

And now we can use the following kinematic formula in order to find the distance travelled:

Assuming the final velocity is 0 we can find the distance like this:
