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3 years ago

Why is it so hot along the equator?

2 answers:

7 0

Its hot because it's closer to the sun and the sun is pretty hot. the rays of the sun project more energy on the equator

iren2701 [21]3 years ago

3 0

Y no me digas nada que te lo digo yo no te quiero ni no su what y el de la selección nacional de la selección de

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Charge q1 is distance r from a positive point charge Q. Charge q2=q1/3 is distance 2r from Q. What is the ratio U1/U2 of their p

worty [1.4K]

We have that The ratio U1/U2 of their potential energies due to their interactions with Q is

$U1/U2=6$
$U1/U2=6$

From the question we are told that

Question 1

Charge q1 is distance r from a positive point charge Q.

Question 2

Charge q2=q1/3 is distance 2r from Q.

Charge q1 is distance s from the negative plate of a parallel-plate capacitor.

Charge q2=q1/3 is distance 2s from the negative plate.

Generally the equation for the potential energy is mathematically given as

$U=\frac{-k*qQ}{r}$

Therefore

The Equations of U1 and U2 is

For U1

$U1=\frac{-k*q_1Q}{r}$

For U2

$U2=\frac{-k*q_1Q}{3*2r}$

Since

U is a function of q and q2=q1/3

Therefore

$U1/U2=6$

For Question 2

For U1

$U1=\frac{-k*q_1Q}{s}\\\\For U2\\\\U2=\frac{-k*q_1Q}{3*2r}$

Therefore

$U1/U2=6$

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7 0

3 years ago

A concave (convergent) mirror has a focus of 3.4 cm. A tree that is 0.5cm tall is situated 4.5 cm away from the mirror. Calculat

Elanso [62]

The image position is 13.9 cm from the mirror

Explanation:

To solve this problem, we can use the mirror equation:

$\frac{1}{f}=\frac{1}{p}+\frac{1}{q}$

where

f is the focal length

p is the distance of the object from the mirror

q is the distance of the image from the mirror

In this problem, we have:

f = 3.4 cm is the focal length of the mirror (positive for a concave mirror)

p = 4.5 cm is the position of the object (the tree)

Solving the equation for q, we find the position of the image:

$\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{3.4}-\frac{1}{4.5}=0.0719 cm^{-1}\\q=\frac{1}{0.0719}=13.9 cm$

Learn more about mirrors:

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3 0

3 years ago

Force is measured in units called

balu736 [363]

Answer:

Newtons

Explanation:

8 0

4 years ago

Read 2 more answers

A block of mass 2. 0 kg, starting from rest, is pushed with a constant force across a horizontal track. The position of the bloc

yan [13]

The magnitude of the change in momentum of the block between zero and 4. 0 seconds is

dp=1.6m/s

<h3>What is the magnitude of the change in momentum of the block between zero and 4. 0 seconds?</h3>

Generally, the equation for the kinematics equation is mathematically given as

x=x+ut+0.5at^2

Therefore

1.6=0+0+0.5*a*1^2

a=0.2m/s^2

In conclusion, change in momentum

dP=mv-mu

2.0*0.8-0

dp=1.6m/s