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Lynna [10]
3 years ago
12

For the past four years, Mr. Thompson has kept a pet boa constrictor in his science classroom. At the beginning of each year, hi

s students measure the length of the snake and record the result. The table below shows the measurements for all four years. Year Length (cm) 1 120 2 190 3 260 4 330 What is the growth pattern of the boa constrictor? It doubles in size every year. The amount it grows changes every year. It grows 70 centimeters each year. It grows 7 centimeters each year.
Physics
2 answers:
umka2103 [35]3 years ago
7 0
It grows 70cm a year. 
maxonik [38]3 years ago
6 0

Answer:               It grows 70 centimeters each year.

Explanation: study island

Have a good week :))

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A vertical spring stretches 4.0 cm when a 12-g object is hung from it. The object is replaced with a block of mass 28 g that osc
marin [14]

Answer:

Time period of the osculation will be 0.0671 sec  

Explanation:

It is given a vertical spring is stretched by 4 cm

So change in length of the spring x = 4 cm = 0.04 m

Mass which is hung from it m = 12 gram = 0.012 kg

Sprig force will be equal to weight of the mass

So kx=mg

k\times 0.04=0.012\times 9.8

k = 244.7 N/m

Now new mass is m = 28 gram = 0.028 kg

So time period with new mass will be

T=2\pi \sqrt{\frac{m}{k}}

=2\times 3.14 \sqrt{\frac{0.028}{244.7}}=0.0671sec

4 0
3 years ago
Brad walks and jogs to schooll every day. He averages 5 km/hr walking and 9 km/hr jogging. The distane from home to shool is 6 k
Vitek1552 [10]
We know that
Distance = speed x time
Let w be the time Brad spent walking. The time spent jogging will be 1 - w
6 = 5w + 9(1 - w)
w = 0.75 hours
Distance walked = 0.75 x 5
= 3.75 km
5 0
3 years ago
What circumstance would allow an officer to search a home even if they didn’t have a warrant?
Ipatiy [6.2K]

Answer:

A

Explanation:

The officer would have had permission regardless of anything else, kind of like letting someone into your house.

5 0
3 years ago
The distance between two stations is 1995 Km. How much time will it take to cover the distance at an average speed of 19KM/hour
Flura [38]
105 hours or 4.375 days
5 0
3 years ago
A car traveling at 14 m/s accelerates at 3.5 m/s² for 5 seconds. How much distance does it travel during that time?​
Rainbow [258]

Answer: 113.75

Explanation:

You know

acceleration = a = 3.5 m/s²

time = t = 5 seconds

initial velocity = u = 14 m/s

Unknown is distance = s = ?

Use equation: s = ut + \frac{1}{2} at²

Substitute all the known values inside the equation:

s = (14*5) + 0.5 * 3.5 * 5²

s = 70 + 43.75 = 113.75 m

The car travels 113.75 metres.

3 0
3 years ago
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