It is given that, a proton in a particular electric field experiences an electric force whose magnitude is equal to the weight of the proton such that,

$qE=mg$

$E=\dfrac{mg}{q}$

$E=\dfrac{1.67\times 10^{-27}\times 9.8}{1.6\times 10^{-19}}$

$E=1.02\times 10^{-7}\ N/C$

$E=10^{-7}\ N/C$

So, the magnitude of electric field at the location of the proton is $10^{-7}\ N/C$ . Hence, this is the required solution.

8 0

4 years ago

What is the mass of a 1.2N book?

const2013 [10]

2.8 kg .............is the mass of a 1.2 N book.

7 0

3 years ago

Read 2 more answers

An airplane is flying in a horizontal circle at a speed of 480 km/h (). If its wings are tilted at angle =40° to the horizontal

german

Answer:

$R = 2162 m$

Explanation:

When wings of the airplane makes an angle of 40 degree with the horizontal so here we can say that force due to air is having two components

$F_y = mg$

$F_x = \frac{mv^2}{R}$

now we know that

$F_y = F cos40$

$F_x = F sin40$

also we know that

$v = 480 km/h$

$v = 133.3 m/s$

now plug in all data in above equations

$tan 40 = \frac{v^2}{Rg}$

$R = \frac{v^2}{g tan40}$

$R = \frac{133.3^2}{9.8 tan40}$

$R = 2162 m$

6 0

3 years ago

write down the following units in the ascending of their value A) mm nm cm um B) 1m 1cm 1km 1mm. convert the following units int

Reptile [31]

Answer:

A) nm, um, mm, cm

B) 1mm, 1cm, 1m, 1km

A) 3500g, B) 2500m, C) 7200 seconds

6 0

3 years ago