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KATRIN_1 [288]
3 years ago
13

Calculate the critical angle for Zircon which has a refractive index of n = 2*

Physics
1 answer:
MA_775_DIABLO [31]3 years ago
8 0

Answer:

Given that refractive index of the material is √2. i.e. n = √2. Hence, critical angle for the material is 45°

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PLEASE HELP!! ITS URGENT!!!​
Natasha2012 [34]

Answer:

F = 800 [N]

Explanation:

To be able to calculate this problem we must use the principle of momentum before and after the impact of the hammer.

We must summarize that after the impact the hammer does not move, therefore its speed is zero. In this way, we can propose the following equation.

ΣPbefore = ΣPafter

(m_{1}*v_{1}) - F*t = (m_{1}*v_{2})

where:

m₁ = mass of the hammer = 0.15 [m/s]

v₁ = velocity of the hammer = 8 [m/s]

F = force [N] (units of Newtons)

t = time = 0.0015 [s]

v₂ = velocity of the hammer after the impact = 0

(0.15*8)-(F*0.0015) = (0.15*0)\\F*0.0015 = 0.15*8\\F = 1.2/(0.0015)\\F = 800 [N]

Note: The force is taken as negative since it is exerted by the nail on the hammer and this force is directed in the opposite direction to the movement of the hammer.

6 0
3 years ago
a book is sitting still on your desk. are the forces acting on the book balanced or unbalanced? explain.
GrogVix [38]
<span>They are balanced. If the forces were not balanced the book would move*. In this example, the downward force of gravity on the book is counterbalanced by the upthrust of the desk. </span>
8 0
3 years ago
Read 2 more answers
I need a correct answer plzzzzzzzzzzzzzzzzzzzz
olya-2409 [2.1K]

Answer:

option 1

Explanation:

i just used the SOH CAH TOA, and since the given is tan=opposite/adjacent, that should be the answer

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3 years ago
Suppose the electric field in problems 2 was caused by a point charge. The test charge is moved to a distance twice as far from
mojhsa [17]

Answer:

it is reduced four times.

Explanation:

By definition, the electric field is the force per unit charge created by a charge distribution.

If the charge creating the field is a point charge, the force exerted by it on a test charge, must obey Coulomb´s Law, so, it must be inversely proportional to the square of the distance between the charges.

So, if the distance increases twice, as the force is inversely proportional to the square of the distance, and the square of 2 is 4, this means that the magnitude of the force exerted on the test charge must be 4 times smaller.

8 0
3 years ago
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Anna35 [415]

Answer:

Not sure but

F = m* a

32= 5 * a

a= 6.4 m/s^2

6 0
3 years ago
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