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s344n2d4d5 [400]
3 years ago
12

A car has a mass of 900 kg and a truck has a mass of 1800 kg. In which of the following situations would they have the same mome

ntum?
The car travels at twice the velocity of the truck.

The car and truck travel at the same velocity.

The truck has a negative acceleration.

The car has a positive acceleration.
Physics
2 answers:
Kaylis [27]3 years ago
7 0

a) since force = mass * acceleration  

f= 900 * 0 (because constant speed = 0 acceleration)  

similarly b) f = 0

Yakvenalex [24]3 years ago
7 0

Answer:

The car travels at twice the velocity of the truck.

Explanation:

As we know that momentum is defined as the product of mass and velocity

so here we know

mass of the car = 900 kg

mass of the truck = 1800 kg

now let say that the speed of car = v_1

speed of truck = v_2

so if the momentum of car and truck is same

900 v_1 = 1800 v_2

v_1 = 2 v_2

so we can say that car will move with double the speed of truck

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3 years ago
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An open organ pipe 30 cm long and a closed organ pipe 23 cm long, both of same diameter , are each sounding its first overtone ,
cupoosta [38]

First overtone of open organ pipe is given as

f_{1o} = \frac{v}{L_1 + 2e}

first overtone of closed organ pipe is given as

f_{1c} = \frac{3v}{4(L_2 + e)}

now they are in unison so we will have

\frac{v}{L_1 + 2e} = \frac{3v}{4(L_2 + e)}

\frac{1}{30 + 2e} = \frac{3}{4(23 + e)}

90 + 6e = 92 + 4e

e = 1 cm

so end correction of both pipes is e = 1 cm

8 0
3 years ago
Motion maps for two objects, Y & Z, are shown.
serg [7]

Answer: it’s 3 seconds

Explanation:

5 0
2 years ago
A 2 kg blue car is moving 6 m/s to the right and collides with a 3 kg red car that is moving 2 m/s to the left. The cars collide
snow_lady [41]

Answer:

Their velocity after the collision is 1.2 m/s, to the right.

Explanation:

Given;

mass of the blue car, m₁ = 2 kg

initial velocity of the blue car, u₁ = 6 m/s

mass of the red car, m₂ = 3 kg

initial velocity of the red car, u₂ = 2 m/s

let the blue car moving to the right be in positive direction

also, let the red car moving to the left be in negative direction

Apply the principle of conservation of linear momentum for inelastic collision.

m₁u₁ - m₂u₂ = v(m₁ + m₂)

where;

v is their velocity after the collision

(2 x 6) - (3 x 2) = v(2 + 3)

12 - 6 = 5v

6 = 5v

v = 6/5

v = 1.2 m/s, to the right

Therefore, their velocity after the collision is 1.2 m/s, to the right.

7 0
3 years ago
Help please!
Talja [164]

The correct expression for the maximum speed of the object during its motion is \frac{FT}{m}.

<h3>Maximum speed of the object</h3>

The maximum speed of the object is determined using the following formulas;

v(max) = Aω

where;

  • A is the amplitude of the motion
  • ω is angular speed

The maximum speed of the object can also be obtained from the maximum net force on the object,

F = ma

where;

  • F is the maximum net force
  • a is the acceleration
  • m is mass of the object

F = m(v/t)

mv = Ft

v = Ft/m

Thus, the correct expression for the maximum speed of the object during its motion is \frac{FT}{m}.

Learn more about maximum speed here: brainly.com/question/4931057

3 0
2 years ago
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