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mylen [45]
1 year ago
12

A student takes notes in class.

Physics
1 answer:
VARVARA [1.3K]1 year ago
5 0

The wrong statement is that sound waves created vibration Option A.

<h3>What are sound waves?</h3>

Sound is a type of waves that moves in compressions and rare factions. This implies that sound is a mechanical wave. Recall that a mechanical wave is one that requires a material medium for propagation. Now we know that if we set the medium into vibration, that is when the sound waves begins to vibrate. That brings us to the idea that it is the vibration that causes the sound waves and not the sound waves that creates the vibration.

Thus, knowing that sound is a mechanical wave which moves through solids liquids and gas and that the vibration of the source of sound is what causes the air to vibrate, we conclude that the wrong statement is that sound waves created vibration Option A.

Learn more about sound waves:brainly.com/question/11797560

#SPJ1

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How to calculate sound of an echo ​
bonufazy [111]

by an echo meter

please flw me and thank my answers

#Genius kudi

5 0
2 years ago
Can someone please help me with science.
alekssr [168]

Answer:

The answers to your questions are given below

Explanation:

22. The energy of an electromagnetic wave and it's frequency are related by the following equation:

E = hf

Where:

E => is the energy

h => is the Planck's constant

f => is the frequency

From the equation i.e E = hf, we can conclude that the energy of a wave is directly proportional to it's frequency. This implies that an increase in the frequency of the wave will lead to an increase in the energy of the wave and also, a decrease in the frequency will lead to a decrease in the energy of the wave.

23. Gamma ray and radio wave are both electromagnetic waves. All electromagnetic waves has a constant speed of 3×10⁸ m/s in space.

Thus, gamma ray and radio wave have the same speed in space.

3 0
3 years ago
10. A hockey puck with mass 0.3 kg is sliding along ice that can be considered frictionless. The puck’s velocity is 20 m/s when
SVEN [57.7K]

Answer:

d = \frac{v^2_i}{2a}= \frac{(20m/s)^2}{2* 3.43 m/s^2}=58.309m

Explanation:

For this case  we can use the second law of Newton given by:

\sum F = ma

The friction force on this case is defined as :

F_f = \mu_k N = \mu_k mg

Where N represent the normal force, \mu_k the kinetic friction coeffient and a the acceleration.

For this case we can assume that the only force is the friction force and we have:

F_f = ma

Replacing the friction force we got:

\mu_k mg = ma

We can cancel the mass and we have:

a = \mu_k g = 0.35 *9.8 \frac{m}{s^2}= 3.43 \frac{m}{s^2}

And now we can use the following kinematic formula in order to find the distance travelled:

v^2_f = v^2_i - 2ad

Assuming the final velocity is 0 we can find the distance like this:

d = \frac{v^2_i}{2a}= \frac{(20m/s)^2}{2* 3.43 m/s^2}=58.309m

5 0
3 years ago
A student throws a rock upwards. The rock reaches a maximum height 2.4 seconds after it was released.
Allisa [31]

Answer:

23.52 m/s

Explanation:

The following data were obtained from the question:

Time taken (t) to reach the maximum height = 2.4 s

Acceleration due to gravity (g) = 9.8 m/s²

Initial velocity (u) =..?

At the maximum height, the final velocity (v) is zero. Thus, we can obtain how fast the rock (i.e initial velocity)

was thrown as follow:

v = u – gt (since the rock is going against gravity)

0 = u – (9.8 × 2.4)

0 = u – 23.52

Collect like terms

0 + 23.52 = u

u = 23.52 m/s

Therefore, the rock was thrown at a velocity of 23.52 m/s.

7 0
3 years ago
Si un auto se mueve en rapidez constante de 25,0m/s a lo largo de 2500 m en línea recta, ¿cuál es la magnitud de la fuerza resul
Nataly_w [17]

Answer:

F= 0

Explanation:

This exercise we use Newton's second law,

            F = m a

in this case as the speed is constant the acceleration is zero therefore the force is zero.

Change we can solve it using Newton's first law, which states that every vehicle remains still or with constant speed if there is no extensive outside acting on it

We see that with any of the two forms the sum of the applied forces is zero

                     ∑ F = 0

3 0
3 years ago
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