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Alexxandr [17]
3 years ago
6

Solve for y. 2(y + 2) = 14

Mathematics
2 answers:
Semenov [28]3 years ago
8 0

2(y+2)=14

2y+4=14

2y=10

y=5

alexandr402 [8]3 years ago
8 0

Answer:

Y=5

Step-by-step explanation:

2(y+2)=14

2y+4=14

2y=14-4

2y=10

2y÷2=10÷2

Y=5

If I was of help plz mark my answer as brainliest

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Solve for x. Round your answer to 2 decimal places.<br> A. 8<br> B. 13.86<br> C. 18.48<br> D. 32
weqwewe [10]

Answer:

D) 32

Step-by-step explanation:

sin∠30=16/x first calculate sin∠30

1/2=16/x next cross multiply

x=32

Have a good day :)

3 0
2 years ago
Help pls I give brainlest
dedylja [7]

Answer:

y = 1/2x - 3

Step-by-step explanation:

The line intercepts with the y-axis at -3 and its pattern is going right two and up one.

6 0
3 years ago
In an arithmetic sequence, t4 + t5 + t6 = 300, and t15 +t16+ t17 = 201. Find t18.
stiks02 [169]
In an arithmetic sequence:
Tn=t₁+(n-1)d

t₄=t₁+(4-1)d=t₁+3d
t₅=t₁+(5-1)d=t₁+4d
t₆=t₁+(6-1)d=t₁+5d

t₄+t₅+t₆=(t₁+3d) +(t₁+4d)+(t₁+5d)=3t₁+12d

Therefore:
3t₁+12d=300    (1)


t₁₅=t₁+(15-1)d=t₁+14d
t₁₆=t₁+(16-1)d=t₁+15d
t₁₇=t₁+(17-1)d=t₁+16d

t₁₅+t₁₆+t₁₇=(t₁+14d)+(t₁+15d)+(t₁+16d)=3t₁+45d

Therefore:
3t₁+45d=201    (2)

With the equations (1) and (2) we make an system of equations:

3t₁+12d=300
3t₁+45d=201

we can solve this system of equations by reduction method.

  3t₁+12d=300
-(3t₁+45d=201)
-----------------------------
       -33d=99      ⇒d=99/-33=-3

3t₁+12d=300
3t₁+12(-3)=300
3t₁-36=300
3t₁=300+36
3t₁=336
t₁=336/3
t₁=112

Threfore:

Tn=112+(n-1)(-3)
Tn=112-3n+3
Tn=115-3n

Now, we calculate T₁₈:

T₁₈=115-3(18)=115-54=61

Answer: T₁₈=61




5 0
3 years ago
Write an equation in slope intercept form with the given information slope=10 and goes through point (1,5)
avanturin [10]
Y-y1=m(x-x1)
y-5=10(x-1)
Y-5=10x-10
Y=10x-5
5 0
3 years ago
What are the solutions to the quadratic equation x^2-16=0
frutty [35]
Simplifying this, we get:
(x+4)(x-4) = 0
Now, to get 0, we can replace x for one of these things to make 0, so:
x can either be 4, or -4
8 0
3 years ago
Read 2 more answers
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