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Colt1911 [192]
3 years ago
5

One bus averages 58 mi/h, and the other bus averages 54 mi/h. When will they be 365 miles apart?

Mathematics
1 answer:
Aleks04 [339]3 years ago
7 0

Answer:

T=3.3 HOURS AFTER THEY LEAVE THEY WILL BE 363 MILES APART

Step-by-step explanation:

internet

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19. If a school board determines that there should be 3 teachers for every 50 students, how many teachers are needed for an enro
WINSTONCH [101]

Answer:

324 teachers

Step-by-step explanation:

3 teachers of every 50 students

__ teachers of 5400 students

so,

5400 \div 50 = 108

therefore,

3 \times 108 = 324

7 0
3 years ago
Read 2 more answers
Miguel is making trail mix. He uses 5 1/3 ounces of nuts and 2 3/4 ounces of raisins. Which
Lady_Fox [76]
It doesn’t show which options?
But the difference would be 2 7/12 or 2.58
4 0
3 years ago
Mike pays $20 per hour for algebra tutoring. The equation y = 20x relates the cost of tutoring (y) to the number of hours (x) he
kotykmax [81]

The unit rate in the equation is 20.

Option C) is the correct answer.

<u>Step-by-step explanation</u>:

Step 1 :

In the given equation y = 20x

where,

x ⇒ total number of hours for tutoring

20 ⇒  the cost per hour of tutoring

y ⇒ the total cost for total hours of tutoring

Step 2 :

Unit rate refers to the value per hour.

Here, the cost for 1 hour of tutoring is $20.

∴ The unit rate is $20 per hour of tutoring.

8 0
4 years ago
Cedric and Josh both ordered the same size pizzas at Marco’s Pizzeria; however, they ordered different toppings. Marco’s charges
Oksanka [162]
Let
C---------> <span>the cost of a pizza
</span>t----------> <span>number of toppings

we know that
</span>$15.74-3t=$14.49-2t
15.74-14.49=3t-2t-------------> t=1.25

the cost of one topping is $1.25
and the cost of one pizza <span>without topping is
</span>15.74-3*1.25--------> $11.99

then
<span>an equation for the cost of a pizza, C, as a function of the number of toppings, t ordered is
</span>C=11.99+1.25t

the answer is 
C=11.99+1.25t
6 0
3 years ago
Read 2 more answers
Shortly after their arrival, Europeans began introducing pigs to the Americas as a source of food. Some escaped, and others were
natka813 [3]

Answer: About 800 thousand

The more accurate value is 807,528 but this is also an approximation.

=======================================================

Work Shown:

t = \text{number of years since the year 2000}

P_0 = \text{population (in millions) in the year 2000}

P = P_0(1.2)^t\\\\5 = P_0(1.2)^{10}\\\\5 \approx P_0*6.1917364224\\\\P_0 \approx \frac{5}{6.1917364224}\\\\P_0 \approx 0.80752791444922\\\\P_0 \approx 0.807528\\\\

That's the rough population of wild pigs (in millions) for the year 2000.

Multiply by 10^6 to get it in terms of units instead.

0.807528\times10^6 = 807,528

There were roughly 800 thousand wild pigs in the year 2000.

7 0
2 years ago
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