L ≥ 5w + 4
2(L+w) ≥ 32
L+w ≥ 16
6w + 4 ≥ 16
6w ≥ 12
w ≥ 2
L ≥ 5w + 4
L ≥ 14
If L = 14 and w = 2 then the perimeter is 32.
These are the smallest dimensions that fit the criteria.
Note: If we raise the width by 1 to w = 3
then the length is at least 19. At 19 by 3 we have P = 44
Like would be appreciated!!
Answer:
21899921030
Step-by-step explanation:
e^(i.π) = -1
2^(-2+3-1) = 2^0 = 1
Therefor
-1 + 1 + 21899921030 = 21899921030
The answer is x=5 and y=-2
The value of x⁴ is equal to 79.8006702
