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2 years ago

Joaquin travels 300 miles in 6 hours. How fast was he going per hour?

Mathematics

2 answers:

Murljashka [212]2 years ago

6 0

Joaquin travels 50 miles per hour

Mariana [72]2 years ago

4 0

Answer:

50 miles per hour

Step-by-step explanation]

300/6=50/1

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Actorize Completely PQ+ PR - RQ -Q²

sp2606 [1]

Answer:

(Q + R)(P - Q)

Step-by-step explanation:

PQ + PR - RQ - Q² = (Q + R)(P - Q)

8 0

2 years ago

What is the solution of the inequality x^3+3x^2>7x+6

sveta [45]

Answer:

x>2

Step-by-step explanation:

x3+3x2=7x+6

x3+3x2−(7x+6)=7x+6−(7x+6)

x3+3x2−7x−6=0

(x−2)(x2+5x+3)=0

x−2=0 or x2+5x+3=0

x=2 or x=−0.6972243622680054 or x=−4.302775637731995

x<−4.302776

−4.302776<x<−0.697224

−0.697224<x<2

x>2(Works in original inequality)

3 0

2 years ago

a village having a population of 4000, requires 150 litres of water per head per day. it has a tank measuring 20m x 15m x 6m. fo

allochka39001 [22]

The water will last for 3 days

Solution:

Given that, village having a population of 4000, requires 150 litres of water per head per day

Let us first find the volume of tank

The tank measuring 20m x 15m x 6m

Length = 20 m

Breadth = 15 m

Height = 6 m

$volume\ of\ tank = length \times breadth \times height$

$Volume\ of\ tank = 20 \times 15 \times 6 = 1800$

Thus volume of tank is 1800 cubic meter

From given,

Water required per person per day = 150 liters

Therefore, water required for 4000 people per day is:

$\rightarrow 4000 \times 150 = 600000 \text{ liters }$

Convert to meters

$600000 \text{ liters } = 600000 \times \frac{1}{1000}\ m^3\\\\600000 \text{ liters } = 600\ m^3$

How many days will the water of this tank last?

$\text{Number of days water will last } = \frac{\text{volume of tank}}{\text{total water required per day}}$

$\text{Number of days water will last } = \frac{1800}{600} = 3$

Thus the water will last for 3 days

5 0

3 years ago

1/8 of Tony's books are mystery books he has three mystery books how many books does Tony have an all

seropon [69]

1/8 of all=mystery
mystery=3

'of' means multiply
therefor
1/8 times all=3
multiply both sides by 8/1 to clear fracion
all=24

6 0

3 years ago

Find all roots: x^3 + 7x^2 + 12x = 0 Show all work and check your answer.

Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

Solution:

We have been given a cubic polynomial.

$x^{3}+7 x^{2}+12 x=0$

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

$x^{3}+7 x^{2}+12 x=0$

$x\left(x^{2}+7 x+12\right)=0$ ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

$x^{2}+7 x+12=0$

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

$\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}$

Therefore, the two roots are:

$\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}$

And,

$\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}$

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0

3 years ago