You need to do the ones in the parentheses first
Answer:4
Step-by-step explanation: Because 4 goes in 3/4 better and more eqvilent to that answer.
Answer: 0.31 or 31%
Let A be the event that the disease is present in a particular person
Let B be the event that a person tests positive for the disease
The problem asks to find P(A|B), where
P(A|B) = P(B|A)*P(A) / P(B) = (P(B|A)*P(A)) / (P(B|A)*P(A) + P(B|~A)*P(~A))
In other words, the problem asks for the probability that a positive test result will be a true positive.
P(B|A) = 1-0.02 = 0.98 (person tests positive given that they have the disease)
P(A) = 0.009 (probability the disease is present in any particular person)
P(B|~A) = 0.02 (probability a person tests positive given they do not have the disease)
P(~A) = 1-0.009 = 0.991 (probability a particular person does not have the disease)
P(A|B) = (0.98*0.009) / (0.98*0.009 + 0.02*0.991)
= 0.00882 / 0.02864 = 0.30796
*round however you need to but i am leaving it at 0.31 or 31%*
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The average speed of Martha and Sarah is 32 km/h.
We need to know about the speed to solve this problem. Speed can be determined as the distance traveled divided by time. It can be written as
v = s / t
where v is speed, s is distance and t is time.
From the question above, we know that:
t sarah = 3 hours
t martha = 5 hours
v sarah = 40 km/h
By using the speed equation, we get the distance
vsarah = s / tsarah
40 = s/3
s = 120 km
Find Martha's speed
vmartha = s / tmartha
vmartha = 120 / 5
vmartha = 24 km/h
Find average speed
v = (vsarah + vmartha)/2
v = (40 + 24) / 2
v = 32 km/h
Hence, the average speed of Martha and Sarah is 32 km/h.
Find more on speed at: brainly.com/question/6504879
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