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poizon [28]
3 years ago
13

In an electrolytic cell, which ion would migrate

Chemistry
1 answer:
Murljashka [212]3 years ago
8 0

Answer:

Silver ion

Explanation:

In an electrolytic cell, the positive ions known as the cations migrate to the negative electrode, the cathode where they accept electrons to become discharged as neutral atoms. Also, the negative ions known as the anions migrate to the positive electrode, the anode, where they give up their electrons to become discharged as neutral atoms.

From the question above, the only positive ion among the options given is the silver ion, Ag+, therefore, it is the correct option.

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Solid iron(III) hydroxide decomposes to produce iron(III) oxide and water vapor. If 0.75 L of water vapor is produced at STP, ho
MaRussiya [10]
The reaction is 2Fe(OH)3 --> Fe2O3 + 3H2O, so the mole ratio of iron (III) hydroxide to water is 2 to 3, or 0.667. That means you need 0.667 moles of iron(III) hydroxide for every mole of water that forms. 

<span>You are missing some info. You need the volume of the water vapor. At STP, 1 Liter of gas contains 22.4 moles, so you can find the moles of water vapor once you know the volume of the water vapor in Liters. </span>

<span>Then, mulitply moles of water by 0.667 to find moles of iron (III) hydroxide used. Finally, multiply by the molar mass of iron (III) hydroxide to find the mass in grams.</span>
8 0
4 years ago
Un atleta se dirige hacia la línea de salida a 6 m/s. Cuando pasa por la marca de 100 m, ponemos el cronómetro en marcha. Escrib
Romashka [77]

Answer:

Los parámetros dados del movimiento son;

La velocidad con la que el atleta se dirige hacia la línea de salida = 6 m / s

El punto en el que se inicia el cronómetro = marca de 100 m

La ecuación para la distancia recorrida, 's', se da como sigue;

s = 6 m / s × t

La distancia total recorrida, d = 100 + s

∴ d = 100 + 6·t

Los gráficos de las ecuaciones se crean con Microsoft Excel y se presentan de la siguiente manera;

Explanation:

4 0
3 years ago
Crystallizing salt from seawater, ripening fruit, and production of elements in the stars are energy/matter changes. These chang
miv72 [106K]

The changes in matter/energy can be classified as follows:

  • Physical changes - Crystallizing salt from seawater
  • Chemical changes - ripening fruit
  • Nuclear changes - production of elements in the stars

<h3>What are physical, chemical and nuclear changes?</h3>

Matter and energy undergo physical, chemical and nuclear changes.

Physical changes are changes in which no new product is formed.

Chemical changes are changes in which no new product is formed.

Nuclear changes are changes in which no new product is formed.

Examples of each of the given changes is as follows:

  • Physical changes - Crystallizing salt from seawater
  • Chemical changes - ripening fruit
  • Nuclear changes - production of elements in the stars

Therefore, matter/energy undergo changes.

Learn more about changes in matter at: brainly.com/question/3998772

#SPJ1

8 0
2 years ago
As the temperature of a gas increases, which of the following explains the effect on the average kinetic energy of the gas?
lidiya [134]
As the temperature of a gas increases, the kinetic energy of the gas particles will also increase. As the temperature of the gas increase, the gas particles gains more energy to move faster, they thus collide more with one another and with the wall of the container, thus increasing pressure as well. So, as the temperature of a gas increases, the kinetic energy increases and the pressure increases as well if the gas is inside an inflexible container. 
8 0
3 years ago
Read 2 more answers
A 5.00g of X, the product of organic synthesis is obtained in a 1.0 dm3 aqueous solution. Calculate the mass of X that can be ex
Anestetic [448]

Answer:

mass of X extracted from the aqueous solution by 50 cm³ of ethoxy ethane = 3.33 g

Explanation:

The partition coefficient of X between ethoxy ethane (ether) and water, K is given by the formula

K = concentration of X in ether/concentration of X in water

Partition coefficient, K(X) between ethoxy ethane and water = 40

Concentration of X in ether = mass(g)/volume(dm³)

Mass of X in ether = m g

Volume of ether = 50/1000 dm³ = 0.05 dm³

Concentration of X in ether = (m/0.05) g/dm³

Concentration of X in water = mass(g)/volume(dm³)

Mass of X in water left after extraction with ether = (5 - m) g

Volume of water = 1 dm³

Concentration of X in water = (5 - m/1) g/dm³

Using K = concentration of X in ether/concentration of X in water;

40 = (m/0.05)/(5 - m)

(m/0.05) = 40 × (5 - m)

(m/0.05) = 200 - 40m

m = 0.05 × (200 - 40m)

m = 10 - 2m

3m = 10

m = 10/3

m = 3.33 g of X

Therefore, mass of X extracted from the aqueous solution by 50 cm³ of ethoxy ethane = 3.33 g

8 0
4 years ago
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