Answer:
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Answer:
We need 41.2 L of propane
Explanation:
Step 1: Data given
volume of H2O = 165 L
Step 2: The balanced equation
C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g)
Step 3: Calculate moles of H2O
1 mol = 22.4 L
165 L = 7.37 moles
Step 4: Calculate moles of propane
For 1 mol C3H8 we need 5 moles O2 to produce 3 moles CO2 and 4 moles H2O
For 7.37 moles H2O we need 7.37/4 = 1.84 moles propane
Step 5: Calculate volume of propane
1 mol = 22.4 L
1.84 moles = 41.2 L
We need 41.2 L of propane
Answer:
The answer is 74.5%.
Explanation:
As we know that % yield=
x 100%.
Therefore,
Step 1 Calculate Theoretical yield:
0.112
x
x
x
= 1.001 g 
Now Step 2
% yield =
x 100% =
= 74.5%
The solubility equilibrium of PbCl
:

![K_{sp}=[Pb^{2+}][Cl^{-}]^{2}](https://tex.z-dn.net/?f=%20K_%7Bsp%7D%3D%5BPb%5E%7B2%2B%7D%5D%5BCl%5E%7B-%7D%5D%5E%7B2%7D%20%20%20)
![[Cl^{-}] = 2.88 * 10^{-2} M](https://tex.z-dn.net/?f=%20%5BCl%5E%7B-%7D%5D%20%3D%202.88%20%2A%2010%5E%7B-2%7D%20M%20)
![[Pb^{2+}]=\frac{[Cl^{-}]}{2} = \frac{2.88 * 10^{-2}}{2}=1.44 *10^{-2}](https://tex.z-dn.net/?f=%20%5BPb%5E%7B2%2B%7D%5D%3D%5Cfrac%7B%5BCl%5E%7B-%7D%5D%7D%7B2%7D%20%3D%20%5Cfrac%7B2.88%20%2A%2010%5E%7B-2%7D%7D%7B2%7D%3D1.44%20%2A10%5E%7B-2%7D%20%20%20%20)
![K_{sp}=[Pb^{2+}][Cl^{-}]^{2}](https://tex.z-dn.net/?f=%20K_%7Bsp%7D%3D%5BPb%5E%7B2%2B%7D%5D%5BCl%5E%7B-%7D%5D%5E%7B2%7D%20%20%20)
= 
= 
So, the corrected solubility product will be 
The intermolecular forces that are responsible for the dissolution of Ethylene glycol in water is hydrogen bonding dipole-dipole forces and dispersion forces.
Both ethylene glycol and water contains the pair of hydrogen and oxygen.
The hydrogen of one atom create a bond with the oxygen of other atom this results in the formation of intra molecular hydrogen bonding.
The electron are non uniformly distributed over the molecule or the atom which results in the fluctuation of the electron density in the atom.
So it creates are dispersion forces which is present all over the molecule this forces helps to increase the strength of the bond formed between the ethylene glycol and water because they have large masses.
Both ethylene glycol and water are polar molecules because of being polar they form dipole and the dipole of both the molecules interact with each other in order to form bond between the atoms which eventually results in the formation dissolution of ethylene glycol in water.
To know more about intermolecular forces, visit,
brainly.com/question/2193457
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Compete Question - which intermolecular forces are responsible for the dissolution of ethylene glycol? select all that apply hydrogen bonding, dipole-dipole, dispersion and Ion dipole interaction.