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saul85 [17]
3 years ago
5

Consider the following chemical reaction:

Chemistry
1 answer:
maria [59]3 years ago
5 0

Answer:

25 : 18

Explanation:

Mole ratio:

It is simply the ratio between moles of any two compounds take part in chemical reaction. It gives the proportion of compounds present.

The given reaction is the burning of octane. Two moles of octane burned in the presence of twenty five moles of oxygen and produced sixteen moles of carbon dioxide and eighteen moles of water.

Chemical equation:

C₈H₁₈ + O₂     →     CO₂ +  H₂O

Balance chemical equation:

2C₈H₁₈ + 25O₂     →     16CO₂ + 18H₂O

The mole ratio of oxygen and water is 25 : 18.

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11-Draw a pedigree chart for 2 parents and 4 offsprings,
seropon [69]

Answer:

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4 0
3 years ago
What volume of propane (C3H8) is required to produce 165 liters of water according to the following reaction? (All gases are at
inna [77]

Answer:

We need 41.2 L of propane

Explanation:

Step 1: Data given

volume of H2O = 165 L

Step 2:  The balanced equation

C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g)

Step 3: Calculate moles of H2O

1 mol = 22.4 L

165 L = 7.37 moles

Step 4: Calculate moles of propane

For 1 mol C3H8 we need 5 moles O2 to produce 3 moles CO2 and 4 moles H2O

For 7.37 moles H2O we need 7.37/4 = 1.84 moles propane

Step 5: Calculate volume of propane

1 mol = 22.4 L

1.84 moles = 41.2 L

We need 41.2 L of propane

6 0
3 years ago
For the balanced equation shown below, if the reaction of 0.112 grams of
Alekssandra [29.7K]

Answer:

The answer is 74.5%.

Explanation:

As we know that % yield=  \frac{actual yield}{theoretical yield} x 100%.

Therefore,

Step 1 Calculate Theoretical yield:

0.112H_{2} x   \frac{1 mol H_{2} }{2.016 g of H{2} }    x    \frac{4 mol H_{2}O }{4 mol H_{2} }    x  \frac{18.02 g H_{2}O }{1 mol H_{2}O}   = 1.001 g H_{2}O

Now Step 2

% yield   =  \frac{actual yield}{theoretical yield} x 100% =   \frac{0.745g}{1.001g} = 74.5%

8 0
3 years ago
A saturated solution of pbcl2 is found to contain 2.88 x 10-2 m chloride ions. what is the correct value of the solubility produ
bazaltina [42]

The solubility equilibrium of PbCl_{2}:

PbCl_{2}(aq)  Pb^{2+}(aq) + 2 Cl^{-}(aq)

K_{sp}=[Pb^{2+}][Cl^{-}]^{2}

[Cl^{-}] = 2.88 * 10^{-2} M

[Pb^{2+}]=\frac{[Cl^{-}]}{2} = \frac{2.88 * 10^{-2}}{2}=1.44 *10^{-2}

K_{sp}=[Pb^{2+}][Cl^{-}]^{2}

= (1.44 * 10^{-2})(2.88*10^{-2})^{2}

= 1.19 * 10^{-5}

So, the corrected solubility product will be 1.19 * 10^{-5}

4 0
3 years ago
which intermolecular forces are responsible for the dissolution of ethylene glycol? select all that apply.
aksik [14]

The intermolecular forces that are responsible for the dissolution of Ethylene glycol in water is hydrogen bonding dipole-dipole forces and dispersion forces.

Both ethylene glycol and water contains the pair of hydrogen and oxygen.

The hydrogen of one atom create a bond with the oxygen of other atom this results in the formation of intra molecular hydrogen bonding.

The electron are non uniformly distributed over the molecule or the atom which results in the fluctuation of the electron density in the atom.

So it creates are dispersion forces which is present all over the molecule this forces helps to increase the strength of the bond formed between the ethylene glycol and water because they have large masses.

Both ethylene glycol and water are polar molecules because of being polar they form dipole and the dipole of both the molecules interact with each other in order to form bond between the atoms which eventually results in the formation dissolution of ethylene glycol in water.

To know more about intermolecular forces, visit,

brainly.com/question/2193457

#SPJ4

Compete Question - which intermolecular forces are responsible for the dissolution of ethylene glycol? select all that apply hydrogen bonding, dipole-dipole, dispersion and Ion dipole interaction.

8 0
1 year ago
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