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3 years ago

Consider the following chemical reaction:

Chemistry

1 answer:

maria [59]3 years ago

5 0

Answer:

25 : 18

Explanation:

Mole ratio:

It is simply the ratio between moles of any two compounds take part in chemical reaction. It gives the proportion of compounds present.

The given reaction is the burning of octane. Two moles of octane burned in the presence of twenty five moles of oxygen and produced sixteen moles of carbon dioxide and eighteen moles of water.

Chemical equation:

C₈H₁₈ + O₂ → CO₂ + H₂O

Balance chemical equation:

2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O

The mole ratio of oxygen and water is 25 : 18.

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4. Finally, convert hemoglobin concentration from g/dL to millimoles per Liter (milliMolar or mM). Hemoglobin has a molecular we

prohojiy [21]

To make 1 Molar solution of hemoglobin ; 1600 grams of hemoglobin will be dissolved in 1 liter of water

The molecular weight of Hemoglobin is approximately 16,000 Daltons, when hemoglobin is converted to mM

16000 Dalton = 16000 ( g/mol )

given that 1 Dalton = 1 g/mol

To make 1 molar solution of hemoglobin using 1 liter of water

1 liter = 1000 grams

16000 Dalton = 16000 g/mol

Hence 16,000 grams of Hemoglobin is required to make 1 Molar solution of hemoglobin using 1 liter of water.

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2 years ago

Use the pull-down boxes to specify states such as (aq) or (s). If a box is not needed leave it blank. If no reaction occurs leav

Andrei [34K]

Answer:

ZnS(s) ⇄ S²⁻(aq) + Zn²⁺(aq)

Explanation:

First, we will write the molecular equation, since it is easier to balance.

2 HBr(aq) + ZnS(s) ⇄ H₂S(aq) + ZnBr₂(aq)

In the full ionic equation we include all ions and molecular species.

2 H⁺(aq) + 2 Br⁻(aq) + ZnS(s) ⇄ 2 H⁺(aq) + S²⁻(aq) + Zn²⁺(aq) + 2 Br⁻(aq)

In the net ionic equation we include only the ions that participate in the reaction and the molecular species.

ZnS(s) ⇄ S²⁻(aq) + Zn²⁺(aq)

6 0

3 years ago

What do green plants capture from the sun?

Elodia [21]

Answer:

light energy

Explanation:

Plants use the energy from the sun to photosynthesize and make food

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8 0

3 years ago

When calcium carbonate is added to hydrochloric acid, calcium chloride, carbon dioxide, and water are produced. CaCO 3 ( s ) + 2

e-lub [12.9K]

Answer: The mass of calcium chloride formed is 15.21 grams.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For calcium carbonate:

Given mass of calcium carbonate = 32.0 g

Molar mass of calcium carbonate = 100 g/mol

Putting values in equation 1, we get:

$\text{Moles of calcium carbonate}=\frac{32.0g}{100g/mol}=0.32mol$

For hydrochloric acid:

Given mass of hydrochloric acid = 10.0 g

Molar mass of hydrochloric acid = 36.5 g/mol

Putting values in equation 1, we get:

$\text{Moles of hydrochloric acid}=\frac{10.0g}{36.5g/mol}=0.274mol$

The given chemical equation follows:

$CaCO_3(s)+2HCl(aq.)\rightarrow CaCl_2(aq.)+H_2O(l)+CO_2(g)$

By Stoichiometry of the reaction:

2 moles of hydrochloric acid reacts with 1 mole of calcium carbonate

So, 0.274 moles of hydrochloric acid will react with = $\frac{1}{2}\times 0.274=0.137mol$ of calcium carbonate

As, given amount of calcium carbonate is more than the required amount. So, it is considered as an excess reagent.

Thus, hydrochloric acid is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of hydrochloric acid produces 1 mole of calcium chloride.

So, 0.274 moles of hydrochloric acid will produce = $\frac{1}{2}\times 0.274=0.137moles$ of calcium chloride.

Now, calculating the mass of calcium chloride from equation 1, we get:

Molar mass of calcium chloride = 111 g/mol

Moles of calcium chloride = 0.137 moles

Putting values in equation 1, we get:

$0.137mol=\frac{\text{Mass of calcium chloride}}{111g/mol}\\\\\text{Mass of calcium chloride}=(0.137mol\times 111g/mol)=15.21g$

Hence, the mass of calcium chloride formed is 15.21 grams.

4 0

3 years ago

When the equation BiCl3 + H2S → Bi2S3 + HCl is the coefficient of HCl will be

Alina [70]

The product Bismuth (III) sulfide ( $Bi_{2}S_{3}$ ) is used as a starting material for the synthesis of other bismuth compounds. It is formed, together with an acid, from a reaction between a Bismuth (III) salt and hydrogen sulfide ( $H_{2}S$ ). In the given reaction, the Bismuth salt used in the reaction is Bismuth (III) chloride ( $BiCl_{3}$ ).

The balanced reaction of $BiCl_{3}$ and $H_{2}S$ is

$2BiCl_{3} + 3H_{2}S --> Bi_{2}S_{3}+ 6HCl$

Thus, the coefficient of HCl in the reaction is 6.

6 0

3 years ago