No solution bc if u multiply the bottom equation by -2, it makes 6x-8y=-4. This caused the x and y to eliminate, leaving 0=2.
Answer:
x = 31
Step-by-step explanation:
2^x > 4^ 15
Rewrite 4 as 2^2
2^x > 2^2^ 15
We know a^b^c = a^(b*c)
2^x > 2^ (2*15)
2^x > 2^30
Since the bases are the same, the exponents must follow the inequality
x> 30
Answer:
y = 8
Step-by-step explanation:
for the triangles to be congruent, 2y + 20 must equal 36.
2y + 20 = 36
subtract 20 from each side of the equation:
2y = 16
divide both sides by 2:
y = 8
F(x) = 4x - 1
g(x) - 2x² + 3
<u>(f · g)(x)</u>
(f · g)(x) = (4x - 1)(2x² + 3)
(f · g)(x) = 4x(2x² + 3) - 1(2x² + 3)
(f · g)(x) = 4x(2x²) + 4x(3) - 1(2x²) - 1(3)
(f · g)(x) = 8x³ + 12x - 2x² - 3
<u>(f/g)(x)</u>
(f/g)(x) = <u>4x - 1</u>
2x² + 3
<u>(g/f)(x)</u>
(g/f)(x) = <u>2x² + 3</u>
4x - 1
(g/f)(x)= ¹/₂x + ¹/₈ + <u> 3¹/₈ </u>
4x - 1
