Question

PLEASE HELP! Find the missing part.

Answer 1

Answer:

Step-by-step explanation:

$\frac{y}{a}= tan~60=\sqrt{3} \\y=a\sqrt{3} ~~~(1)\\\frac{y}{b} =tan~30\\y=\frac{b}{\sqrt{3} } ~~~(2)\\from~(1)~and~(2)\\a\sqrt{3} =\frac{b}{\sqrt{3} } \\b=a\sqrt{3} \times\sqrt{3} =3a\\a+b=15\\a+3a=15\\4a=15\\a=\frac{15}{4} \\b=3a=3 \times \frac{15}{4} =\frac{45}{4}\\y=a\sqrt{3} =\frac{15\sqrt{3}}{4} \\\frac{x}{15} =sin~30\\x=15 \times \frac{1}{2}=\frac{15}{2}\\\frac{z}{15}=cos~30\\z=15 \times \frac{\sqrt{3}}{2}=\frac{15\sqrt{3} }{2}$