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vagabundo [1.1K]
3 years ago
11

How to round to the naerst 10?

Mathematics
1 answer:
Blababa [14]3 years ago
3 0
So, say your # was 6,234,578. you would go to the seven and look to the number next to in, so 8, and if the neighbor is 5 or bigger, you make the number, in this case a 7 an 8. Last, you make all the other #s after the one you rounded 0. So the answer would be:

6,234,570.0
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Raheem made 14 ounces of curry sauce which contained (among other things), 3.25 ounces of spices. He wants to make a larger batc
wolverine [178]

Answer:

19.5 ounces of spices

Step-by-step explanation:

Raheem made 14 ounces of curry sauce which contained (among other things), 3.25 ounces of spices. He wants to make a larger batch for a family dinner and decides he will need a total of 84 ounces of sauce altogether. How many ounces of spices will he need to complete his recipe?

The question above is calculated as:

14 ounces of sauce = 3.25 ounces of spices

84 ounces of sauce = x ounces of spices

Cross Multiply

14x = 84 × 3.25

x = 84 × 3.25/14

x = 19.5 ounces of spices

Hence, for 84 ounces of curry sauce he would need 19.5 ounces of spices

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Find the area of the shaded sector of the circle. Leave your answer in terms of pi.
pentagon [3]
We know that
area  of circle =pi*r²
for r=4 ft
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<span>the shaded sector of the circle represent 3/4 of the total area
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the answer is
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3 years ago
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A lifeguard fills a pool with water at a constant rate. After 1/2 hour, 1/3 of the pool is filled.
Romashka-Z-Leto [24]

Answer: 2/3 of an hour.

Step-by-step explanation: The constant rate of the lifeguard filling the pool is 1/3 of the pool every 1/2 hour.  If she fills it for an hour, she'll get 2/3 of the pool filled.  Therefore, it'll take the lifeguard 1 hour to fill the pool 2/3 of the way.

Hope this helps! :)

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In the figure below, F is between E and G, and G is between F and H. IF EH=9, FH = 7, and EG=6, find FG.
shutvik [7]

Answer:

EH = 9

FH = 7

EG = 6

EF = EH - FH

EF = 9 -7

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FG = EG -EF

FG = 6 -2

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Step-by-step explanation:

3 0
4 years ago
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