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vagabundo [1.1K]
3 years ago
11

How to round to the naerst 10?

Mathematics
1 answer:
Blababa [14]3 years ago
3 0
So, say your # was 6,234,578. you would go to the seven and look to the number next to in, so 8, and if the neighbor is 5 or bigger, you make the number, in this case a 7 an 8. Last, you make all the other #s after the one you rounded 0. So the answer would be:

6,234,570.0
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That would be x=0.87358
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What is the nearest whole percent of 62
charle [14.2K]
The nearest whole percent would just be 62%
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the initial vertical velocity of a rocket shot straight up is 42 meters per second. How long does it take for the rocket to retu
Snowcat [4.5K]
It takes 4.3 seconds for the rocket to return to earth.

The equation is:
0=-9.8t^2+v_0t+h_0
where -9.8m/sec² is the acceleration due to gravity, v₀ is the initial velocity, and h₀ is the initial height.  We will go from the assumption that the rocket is launched from the ground, so h₀=0, and we are told that the initial velocity, v₀, is 42.  This gives us:

0=-9.8t^2+42t

We will use the quadratic formula to solve this.  The quadratic formula is:
x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Plugging in our information we have:
t=\frac{-42\pm \sqrt{42^2-4(-9.8)(0)}}{2(-9.8)}
\\
\\=\frac{-42\pm \sqrt{1764-0}}{-19.6}
\\
\\=\frac{-42\pm \sqrt{1764}}{-19.6}
\\
\\=\frac{-42\pm 42}{-19.6}=\frac{-42-42}{-19.6} \text{ or } \frac{-42+42}{-19.6}
\\
\\=\frac{-84}{-19.6}\text{ or }\frac{0}{-19.6}
\\
\\=4.3\text{ or }0

x=0 is when the rocket is launched; x=4.3 is when the rocket lands.
8 0
3 years ago
If the terminal side of angle θ passes through a point on the unit circle in the first quadrant where x=√2/2, what is the exact
Serhud [2]

The exact measure of the angle is 45°.

<h3>How to get the angle?</h3>

We know that the terminal side passes through a point of the form (√2/2, y).

Notice that the point is on the unit circle, so its module must be equal to 1, so we can write:

1 = \sqrt{( \frac{\sqrt{2} }{2} )^2 + y^2} \\\\1^2 = \frac{2}{4} + y^2\\1 - 1/2 = y^2\\\\1/\sqrt{2} = y

We know that y is positive because the point is on the first quadrant.

Now, we know that our point is:

(√2/2, 1/√2)

And we can rewrite:

√2/2 = 1/√2

So the point is:

( 1/√2,  1/√2)

Finally, remember that a point (x, y), the angle that represents it is given by:

θ = Atan(y/x).

Then in this case, we have:

θ = Atan(1/√2/1/√2) = Atan(1) = 45°

If you want to learn more about angles, you can read:

brainly.com/question/17972372

3 0
2 years ago
A polynomial equation has only imaginary roots and no real root. Which options CANNOT be the degree of that polynomial? (Select
puteri [66]

we know that

Imaginary roots will come in pairs, and so the degree must be even.

therefore

the answer is

options

B. 3

E. 7

7 0
3 years ago
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