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Misha Larkins [42]
3 years ago
7

Balance the reaction for the combustion of pentane: ?C5H12+?O2→?CO2+?H2O Enter the four coefficients in order, separated by comm

as (e.G., 1,2,3,4), where 1 indicates the absence of a coefficient.
Chemistry
1 answer:
Daniel [21]3 years ago
6 0

Answer:

The four coefficients in order, separated by commas are 1, 8, 5, 6

Explanation:

We count the atoms in order to balance this combustion reaction. In combustion reactions, the products are always water and carbon dioxide.

C₅H₁₂  +  ?O₂→  ?CO₂ + ?H₂O

We have 12 hydrogen in right side and we can balance with 6 in the left side. But the number of oxygen is odd. We add 2 in the  right side, so we have 24 H, and in the product side we add a 12.

As we add 2 in the C₅H₁₂, we have 10 C, so we must add 10 to the CO₂ in the product side.

Let's count the oxygens: 20 from the CO₂ + 12 from the water = 32.

We add 16 in the reactant side. Balanced equation is:

2C₅H₁₂  + 16O₂→  10CO₂ + 12H₂O

We also can divide by /2 in order to have the lowest stoichiometry

C₅H₁₂  + 8O₂→  5CO₂ + 6H₂O

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Answer: The mass of ice you would need to add to bring the equilibrium temperature of the system to 300 K is 16.14 \times 10^{4} kg.

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                 q = m \times S \times \Delta T

As density of water is 1 kg/L and volume is given as 400,000 L. Therefore, mass of water is as follows.

          Mass of water = Volume × Density

                                  = 400,000 L \times 1 kg/L

                                  = 400,000 kg

or,                              = 400,000 \times 10^{3} g    (as 1 kg = 1000 g)

Specific heat of water is 4.2 J/gm K. Therefore, change in temperature is as follows.

         \Delta T = 305 K - 273 K

                    = 32 K

Now, putting the given values into the above formula and calculate the heat energy as follows.

            q = m \times S \times \Delta T

                = 400,000 \times 10^{3} \times 4.2 \times 32 K

                = 5376 \times 10^{7} J

or,            = 5376 \times 10^{4} kJ

According to the enthalpy of melting of ice 333 kJ/Kg of energy absorbed by by 1 kg of ice. Hence, mass required to absorb energy of 5376 \times 10^{4} kJ  is calculated as follows.

            Mass = \frac{5376 \times 10^{4} kJ}{333 kJ/Kg} \times 1 kg

                      = 16.14 \times 10^{4} kg

Thus, we can conclude that the mass of ice you would need to add to bring the equilibrium temperature of the system to 300 K is 16.14 \times 10^{4} kg.

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3 years ago
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