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Alinara [238K]
3 years ago
15

Please Hurry this is already overdue

Chemistry
1 answer:
Troyanec [42]3 years ago
7 0

Answer:

According to the chart, the period and string length are not the same. Regardless of string length. The chart says that "period = seconds 10"

Explanation:

So for example in Trial 1. The period equaled 8.7, so in turn you would times 8.7 by 10 and get 87. Which is not equal to the string length. For they are also measured in two different measurements.

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What happens to the rate of dissolution as the temperature is increased in a gas solution?
Nina [5.8K]

Answer:

The rate decreases

Explanation:

When we dissolve a gas in a water, the process is exothermic. This implies that heat is evolved upon dissolution of a gas in water.

Recall from Le Chateliers principle that for exothermic reactions, an increase in temperature favours the reverse reaction. The implication of these is that when the temperature of the gas is increased, less gas will dissolve in water.

Hence increase in temperature decreases the rate of solubility of a gas in water.

8 0
3 years ago
What do all four of these types of molecules have in common?
nalin [4]
D. They all contain carbon as an important part of their structure.
3 0
3 years ago
An astronaut weighs 104 newtons on the moon,where the strength of gravity is 1.6 newtons per kilogram
belka [17]
I'd say he ways about 35 kilograms, but I'm probably wrong, xD

6 0
3 years ago
Read 2 more answers
WILL MARK BRANILEST
ahrayia [7]

Answer:

FeCl3 is the limiting reactant

O2 is in excess

Theoretical yield Cl2 = 9.84 grams

The % yield is 96.5 %

Explanation:

Step 1: Data given

Mass of FeCl3 = 15.0 grams

Moles O2 = 4.0 moles

Mass of Cl2 produced = 9.5 grams

Step 2: The balanced equation

4FeCl3 + 3O2 → 2Fe2O3 + 6Cl2

Step 3: Calculate moles FeCl3

Moles FeCl3 = mass FeCl3 / molar mass FeCl3

Moles FeCl3 = 15.0 grams / 162.2 g/mol

Moles FeCl3 = 0.0925 moles

Step 4: Calculate limiting reactant

FeCl3 is the limiting reactant. Because we have way more (more than ratio 3:4) moles O2 than FeCl3. It will completely be consumed (0.0925 moles). O2 is in excess. There will react = 0.069375 moles O2

There will remain 4.0 - 0.069375 = 3.930625 moles

Step 5: Calculate moles Cl2

For 4 moles FeCl3 we need 3 moles O2 to produce 2 moles Fe2O3 and 6 moles Cl2

For 0.0925 moles FeCl3 moles we'll have 6/4 * 0.0925 = 0.13875 moles Cl2.

Step 6: Calculate mass Cl2

Mass Cl2 = moles * molar mass

Mass Cl2 = 0.13875 moles * 70.9 g/mol

Mass Cl2 = 9.84 grams

Step 7: Calculate % yield

% yield = (actual yield / theoretical yield) * 100%

% yield = (9.5 grams / 9.84 grams ) * 100%

% yield = 96.5 %

The % yield is 96.5 %

4 0
3 years ago
What is the percentage error of a length measure of 0.229 cm if the correct value is 0.225 cm
olchik [2.2K]
((|Vtrue-Vobserved|) / (Vtrue)) x 100

1.77777%error
8 0
3 years ago
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