Answer: • using beaker tongs to handle the hot beaker.
• checking the beaker for chips prior to heating on the hot plate.
• Turning off the hot plate after use
Explanation:
The options that will ensure laboratory safety during the experiment will be:
• using beaker tongs to handle the hot beaker.
• checking the beaker for chips prior to heating on the hot plate.
• Turning off the hot plate after use.
We should note that the beaker tongs are simply used in the holding of the beakers that have hot liquids in them. Also, it s vital for the hot plate to be turned off after its use so as to prevent accident.
Answer:
1.57772 m
Explanation:
M = Mass of actor = 84.5 kg
m = Mass of costar = 55 kg
v = Velocity of costar
V = Velocity of actor
= Intial height of actor = 4.3 m
g = Acceleration due to gravity = 9.81 m/s²
As the energy of the system is conserved

As the linear momentum is conserved

Applying conservation of energy again

The maximum height they reach is 1.57772 m
Choice-C is a correct statement.
Assuming that reaching a height 0 doesn’t stop the ball, and that it accelerates at 9.8 m/s^2, the ball would be traveling at 0.5 + 0.7*9.8 = 7.36 m/s downwards.
Answer:
Acceleration=24.9ft^2/s^2
Angular acceleration=1.47rads/s
Explanation:
Note before the ladder is inclined at 30° to the horizontal with a length of 16ft
Hence angular velocity = 6/8=0.75rad/s
acceleration Ab=Aa +(Ab/a)+(Ab/a)t
4+0.75^2*16+a*16
0=0.75^2*16cos30°-a*16sin30°---1
Ab=0+0.75^2sin30°+a*16cos30°----2
Solving equation 1
(0.75^2*16cos30/16sin30)=angular acceleration=a=1.47rad/s
Also from equation 2
Ab=0.75^2*16sin30+1.47*16cos30=24.9ft^2/s^2