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a_sh-v [17]
3 years ago
10

Steve is whirling a rubber cork, tied with a string to his finger, over his head as shown in the figure. The motion of the cork

is similar to the motion of a planet in the solar system around the sun. Which force in the solar system is similar to the tension in the string?
Physics
2 answers:
I am Lyosha [343]3 years ago
6 0

The tension in the string corresponds to the gravitational attraction between the Sun and any planet.

Ainat [17]3 years ago
5 0

Answer:

<h2>Gravitational Force.</h2>

Explanation:

While Steve is whirling a rubber cork, it developes a situation which is similar to the Solar System. In the rubber cork movement, there's "circular" motion which is possible thanks to the string, that is, the string works as "attraction force", allowing the system to maintain its movement.

Now, in the Solar System, the graviational force is like the string, it's the physical magnitude that maintains planets on their movements, attached to the Sun someway.

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Help!!! I need it today <br> Thank you in advance
svlad2 [7]

Answer:

 F = - k (x-xo) a graph of the weight or applied force against the elongation obtaining a line already proves Hooke's law.

Explanation:

The student wants to prove hooke's law which has the form

          F = - k (x-xo)

To do this we hang the spring in a vertical position and mark the equilibrium position on a tape measure, to simplify the calculations we can make this point zero by placing our reference system in this position.

Now for a series of known masses let's get them one by one and measure the spring elongation, building a table of weight vs elongation,

we must be careful when hanging the weights so as not to create oscillations in the spring

we look for the mass of each weight

         W = mg

          m = W / g

and we write them in a new column, we make a graph of the weight or applied force against the elongation and it should give a straight line; the slope of this line is sought, which is the spring constant.

The fact of obtaining a line already proves Hooke's law.

5 0
2 years ago
A runner is jogging in a straight line at a
soldi70 [24.7K]

Answer:

13 km

Explanation:

The bird flies from the runner, to the finish line, and back to the runner.  We can write two equations for the distance it travels:

d = 7.8 km + 7.8 km − 4.9 km/hr × t

d = 24.5 km/hr × t

Solve for t in the second equation and substitute into the first:

t = d / 24.5

d = 7.8 + 7.8 − 4.9 (d / 24.5)

d = 15.6 − 0.2 d

1.2 d = 15.6

d = 13

The bird flies a cumulative distance of 13 km.

4 0
3 years ago
Stars are held together by the force ___, ___ and the composition determine the amount of ___.
Alexus [3.1K]
A star is a large ball of gas that generates its own energy by fusing hydrogen atoms to make helium. It is held together by its own gravity. ... Stars come in a variety of sizes and compositions, which determine their amount of energy and gravity.
4 0
3 years ago
In the table below,which statement would best fill the missing box under isolated systems?
Nostrana [21]

Answer:

b-energy is not exchanged

Explanation:

An isolated system is a thermodynamic system in which neither energy nor matter is exchanged with the surroundings.

As such the best statement that will fill the box under an isolated system is that energy is not exchanged.

  • In an open system, both matter and energy are exchanged with the surrounding.
  • A closed system is one in which energy transfer is permissible but matter is not exchanged.
  • Energy cannot be created nor destroyed in any system. They are simply transformed.
3 0
3 years ago
A tennis ball is thrown from a 25 m tall building with a zero initial velocity. At the same moment, another ball is thrown from
Nataly [62]

Answer:

The two balls meet in 1.47 sec.

Explanation:

Given that,

Height = 25 m

Initial velocity of ball= 0

Initial velocity of another ball = 17 m/s

We need to calculate the ball

Using equation of motion

s=ut+\dfrac{1}{2}gt^2+h

Where, u = initial velocity

h = height

g = acceleration due to gravity

Put the value in the equation

For first ball

s_{1}=0-\dfrac{1}{2}gt^2+25....(I)

For second ball

s_{2}=17t-\dfrac{1}{2}gt^2+0....(II)

From equation (I) and (II)

-\dfrac{1}{2}gt^2+25=17t-\dfrac{1}{2}gt^2+0

t=\dfrac{25}{17}

t=1.47\ sec

Hence, The two balls meet in 1.47 sec.

6 0
3 years ago
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