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2 years ago

A different children's party cost £225.50 How many children were at the party?

1 answer:

8 0

Hi, I think you forgot to write a part of the problem, could you write the rest in the comments please. I would be happy to help you

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Please help me solve these problems

vovangra [49]

Will do first question of each concept only because the rest of the questions are the same concept (the same few repeat but whatever).

1. Total angle = (n - 2) * 180 --> 4 * 180 = 360°

70 + 130 + 120 + θ = 360 --> 320 + θ = 360 --> θ = 40

4. Total angle = (10 - 2) * 180 --> 8 * 180 = 1440

1440/10 = 144°

6. Interior: (n - 2) * 180 --> 10 * 180 = 1800

Exterior: 12 * 180 = 2160 --> 2160 - 1800 = 360

9. (n - 2) * 180 --> 3 * 180 = 540

90 + 90 + 150 + 160 + θ = 540 --> 490 + θ = 540 --> θ = 50

13. Interior: (n - 2) * 180 --> 2 * 180 = 360

Exterior: n * 180 - (n - 2) * 180 --> 180n - 180n + 360 --> 360 (always the same)

16. 7r + 4r + 8r + 5r = 360 --> 24r = 360 --> r = 15

5 0

3 years ago

Please help no link as answers

Katarina [22]

Step-by-step explanation:

You can imagine this figure as a rectangle and cube

If you want volume of this irregular figure than you have to do it like this:

V(figure)= V(rectangle)+ V(cube)

V(figure)= a*b*c+ a³

V(figure)= 4*3*(I don't see dimension on the left)+ 3³

V(figure)=12*(I don't see dimension on the left)+ 27

And only you have to to do is to set this dimension which I can't see.

6 0

2 years ago

Find the 72nd term of the arithmetic sequence -27, -11, 5,

mixas84 [53]

Answer:

1109

Step-by-step explanation:

an = d (n - 1) + c

an = what you're looking for

n = term position

d = the common difference, in your case, 16

c = first term of the sequence, or -27

a₇₂ = 16(72 - 1) + -27 = 1109

5 0

3 years ago

Steve likes to entertain friends at parties with "wire tricks." Suppose he takes a piece of wire 60 inches long and cuts it into

Alex_Xolod [135]

Answer:

a) the length of the wire for the circle = $(\frac{60\pi }{\pi+4}) in$

b)the length of the wire for the square = $(\frac{240}{\pi+4}) in$

c) the smallest possible area = 126.02 in² into two decimal places

Step-by-step explanation:

If one piece of wire for the square is y; and another piece of wire for circle is (60-y).

Then; we can say; let the side of the square be b

so 4(b)=y

b= $\frac{y}{4}$

Area of the square which is L² can now be said to be;

$A_S=(\frac{y}{4})^2 = \frac{y^2}{16}$

On the otherhand; let the radius (r) of the circle be;

2πr = 60-y

$r = \frac{60-y}{2\pi }$

Area of the circle which is πr² can now be;

$A_C= \pi (\frac{60-y}{2\pi } )^2$

$=( \frac{60-y}{4\pi } )^2$

Total Area (A);

A = $A_S+A_C$

= $\frac{y^2}{16} +(\frac{60-y}{4\pi } )^2$

For the smallest possible area; $\frac{dA}{dy}=0$

∴ $\frac{2y}{16}+\frac{2(60-y)(-1)}{4\pi}=0$

If we divide through with (2) and each entity move to the opposite side; we have:

$\frac{y}{18}=\frac{(60-y)}{2\pi}$

By cross multiplying; we have:

2πy = 480 - 8y

collect like terms

(2π + 8) y = 480

which can be reduced to (π + 4)y = 240 by dividing through with 2

$y= \frac{240}{\pi+4}$

∴ since $y= \frac{240}{\pi+4}$ , we can determine for the length of the circle ;

60-y can now be;

= $60-\frac{240}{\pi+4}$

= $\frac{(\pi+4)*60-240}{\pi+40}$

= $\frac{60\pi+240-240}{\pi+4}$

= $(\frac{60\pi}{\pi+4})in$

also, the length of wire for the square (y) ; $y= (\frac{240}{\pi+4})in$

The smallest possible area (A) = $\frac{1}{16} (\frac{240}{\pi+4})^2+(\frac{60\pi}{\pi+y})^2(\frac{1}{4\pi})$

= 126.0223095 in²

≅ 126.02 in² ( to two decimal places)

4 0

3 years ago

15 POINTS-

Doss [256]

I think it’s $3.55
I think this because if u subtract 2.45- 45% = 1.10 sooo u will have to add $1.10 to 2.25 and that will add up the 45% that Walmart is paying with the original price.

8 0

2 years ago

A different children's party cost £225.50 How many children were at the party?​

A different children's party cost £225.50 How many children were at the party?