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3 years ago

A motarcycle covers a distance of 1.8km in 5minutes.Calculate its average velocity

Physics

1 answer:

MissTica3 years ago

8 0

Answer:

0.6 m/s

Explanation:

1.8 km = 1800 m

5 minutes= 300 s

Now,

Velocity = Displacement / time

= 1800/300

= 0.6 m /s

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A hammer falls from a construction worker's hand 30m above the ground at the same time that a filled soft drink can is projected

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For harmer:-

initial velocity=u=0m/s

Acceleration due to gravity=10m/s^2

Now

$\\ \sf\longmapsto s=ut+\dfrac{1}{2}gt^2$

$\\ \sf\longmapsto s=0t+\dfrac{1}{2}(10)t^2$

$\\ \sf\longmapsto s=5t^2\dots(1)$

For soft drink:-

u=24m/s

$\\ \sf\longmapsto 30-s=(24)t+\dfrac{1}{2}(10)t^2$

Using eq(1)

$\\ \sf\longmapsto 30-5t^2=24t-5t^2$

$\\ \sf\longmapsto 24t=30$

$\\ \sf\longmapsto t=\dfrac{30}{24}$

$\\ \sf\longmapsto t=1.2s$

After 1.2s they will meet.

Now

putting t in eq(1)

$\\ \sf\longmapsto s=5t^2=5(1.2)^2=5(1.44)=7.2m$

At the height of 7.2m they will meet

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3 years ago

What are the three most important types of units in radiobiology? Explain the meaning of each.

Rom4ik [11]

Answer:

Most adverse health effects of radiation exposure may be grouped in two general categories:

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3 years ago

People have proposed driving motors with the earth's magnetic field. This is possible in principle, but the small field means th

fiasKO [112]

Answer:

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Explanation:

$\tau$ = Torque = $1\times 10^{-3}\ N/m$

B = Magnetic field of Earth = $5\times 10^{-5}\ T$

A = Area

d = Diameter = 20 cm

Current is given by

$I=\dfrac{\tau}{BA}\\\Rightarrow I=\dfrac{1\times 10^{-3}}{5\times 10^{-5}\times \dfrac{\pi}{4}\times 0.2^2}\\\Rightarrow I=636.619772368\ A$

The current is 636.619772368 A

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3 years ago

The amount of erosion created by a river is affected by all of the following except

SashulF [63]

Answer:

This answer to this one should be Volume of Water.

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3 years ago

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A 26.4 g silver ring (cp = 234 J/kg·°C) is heated to a temperature of 66.2°C and then placed in a calorimeter containing 4.94 ✕

Slav-nsk [51]

Answer:

The final temperature of the mixture = 64.834 °C.

Explanation:

Heat lost by the silver ring = heat gained by the water + heat transferred to the surrounding.

c₁m₁(t₁-t₃) = c₂m₂(t₃-t₂) + Q..............Equation 1

Where c₁ = specific heat capacity of the silver copper, m₁ = mass of the silver copper, t₁ = initial temperature of the silver copper, t₃ = final temperature of the mixture. c₂ = specific heat capacity of water, t₂ = initial temperature of water, m₂ = mass of water, Q = energy transferred to the surrounding.

making t₃ the subject of the equation,

t₃ = [c₁m₁t₁+c₂m₂t₂-Q]/(c₁m₁+c₂m₂)........................ Equation 2

Given: c₁ = 234 J/kg.°C, m₁ = 26.4 g, t₁ = 66.2 °C, c₂ = 4200 J/K.°C, m₂ = 4.92×10⁻² kg, t₂ = 24.0 °C, Q = 0.136 J.

Substituting into equation 2

t₃ = [(234×26.4×66.2)+(4200×0.0492×24)-0.136]/[(234×26.4)+(4200×0.0492)]

t₃ = (408957.12+4959.36-0.136)/(6177.6+206.64)

t₃ = (413916.48-0.136)/6384.24

t₃ = 413916.34/6384.24

Thus the final temperature of the mixture = 64.834 °C.

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3 years ago

A motarcycle covers a distance of 1.8km in 5minutes.Calculate its average velocity ​

A motarcycle covers a distance of 1.8km in 5minutes.Calculate its average velocity