1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mote1985 [20]
3 years ago
5

People have proposed driving motors with the earth's magnetic field. This is possible in principle, but the small field means th

at unrealistically large currents are needed to produce noticeable torques. Suppose a 20-cm-diameter loop of wire is oriented for maximum torque in the earth's field.What current would it need to carry in order to experience a very modest 1.0?
Physics
1 answer:
fiasKO [112]3 years ago
8 0

Answer:

636.619772368 A

Explanation:

\tau = Torque = 1\times 10^{-3}\ N/m

B = Magnetic field of Earth = 5\times 10^{-5}\ T

A = Area

d = Diameter = 20 cm

Current is given by

I=\dfrac{\tau}{BA}\\\Rightarrow I=\dfrac{1\times 10^{-3}}{5\times 10^{-5}\times \dfrac{\pi}{4}\times 0.2^2}\\\Rightarrow I=636.619772368\ A

The current is 636.619772368 A

You might be interested in
True or false a solid object can cast a shadow
elena55 [62]
That would be true because a solid object can cast a shadow
7 0
3 years ago
Read 2 more answers
Roseanne heated a solution in a beaker as part of a laboratory experiment on energy transfer. After a while, she noticed the liq
sveta [45]
I think it is convection hope I could help.
6 0
3 years ago
At what condition does a body becomes weightless at the equator?
ArbitrLikvidat [17]

Answer:

The decrease is due to the bulge at the equator (putting more distance between the rest of the planet and the surface

Explanation:

4 0
3 years ago
WEATHER: <br> What kind of weather occurs along this type of front?
Radda [10]
Cold front because the warm front or hit front is lower on the right and goes downwards and cold front is in the middle and goes to Minneapolis
4 0
3 years ago
Read 2 more answers
A circular coil of radius 5.0 cm and resistance 0.20 Ω is placed in a uniform magnetic field perpendicular to the plane of the c
Romashka [77]

Answer:

Explanation:

Given that,

Assume number of turn is

N= 1

Radius of coil is.

r = 5cm = 0.05m

Then, Area of the surface is given as

A = πr² = π × 0.05²

A = 7.85 × 10^-3 m²

Resistance of

R = 0.20 Ω

The magnetic field is a function of time

B = 0.50exp(-20t) T

Magnitude of induce current at

t = 2s

We need to find the induced emf

This induced voltage, ε can be quantified by:

ε = −NdΦ/dt

Φ = BAcosθ, but θ = 90°, they are perpendicular

So, Φ = BA

ε = −NdΦ/dt = −N d(BA) / dt

A is a constant

ε = −NA dB/dt

Then, B = 0.50exp(-20t)

So, dB/dt = 0.5 × -20 exp(-20t)

dB/dt = -10exp(-20t)

So,

ε = −NA dB/dt

ε = −NA × -10exp(-20t)

ε = 10 × NA exp(-20t)

Now from ohms law, ε = iR

So, I = ε / R

I = 10 × NA exp(-20t) / R

Substituting the values given

I = 10×1× 7.85 ×10^-3×exp(-20×2)/0.2

I = 1.67 × 10^-18 A

6 0
3 years ago
Other questions:
  • What occurs along a convergent plate?
    11·1 answer
  • What happens when you push a spring? How is this different than pulling it? (Hooke’s Law)
    14·2 answers
  • To measure specific heat, the student flows air with a velocity of 20 m/s and a temperature of 25C perpendicular to the length
    14·1 answer
  • 2013 Indianapolis 500 champion Tony Kanaan holds his hand out of his IndyCar while driving through still air with standard atmos
    11·1 answer
  • 1.
    11·1 answer
  • The mass of the boy is 35 kilograms. What is the force of friction that slowed him down?
    9·1 answer
  • Describe the relationship between the forces of attraction and the kinetic energy of particles in a solid, a liquid and a gas
    12·1 answer
  • What is the final temperature if it requires 5000 J of heat to warm 2.38892 x10-2 kg of water that starts at 5oC? Remember Cp fo
    7·1 answer
  • How many joules are there in 200kj
    6·2 answers
  • Objects 1 and 2 attract each other with a electrostatic force of 72.0 units. if the charge of object 1 is halved, then the elect
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!