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3 years ago

What is the power of 10 when 157,821 is written in scientific notation?

Physics

2 answers:

vlabodo [156]3 years ago

3 0

Answer:

The power of 10 in the given value is 5.

Explanation:

scientific notation is expressed in the decimal form. That means always written in the power of 10 form. The decimal place is put after 1 digit.

qaws [65]3 years ago

3 0

Answer:

1.57821 * 10^5 (5)

Explanation:

Scientific notation is defined as the representation in which a number is expressed in the decimal form. That means always written in the power of 10 form. The decimal place is put after 1 digit.

We are given a numerical value of 157,821

Converting this into scientific notation, we get:

Hence, the power of 10 in the given numerical value is 5.

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2 years ago

A flat sheet of paper of area 0.250 m2 is oriented so that the normal to the sheet is at an angle of 60 to a uniform electric fi

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Answer:

a. 1.75 Nm²/C

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Explanation:

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3 years ago

Two neutron stars are separated by a distance of 1.0 x 1012 m. They each have a mass of 1.0 x 1028 kg and a radius of 1.0 x 103

son4ous [18]

To develop this problem it is necessary to apply the concepts related to Gravitational Potential Energy.

Gravitational potential energy can be defined as

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As M=m, then

$PE = -\frac{Gm^2}{R}$

Where,

m = Mass

G =Gravitational Universal Constant

R = Distance /Radius

PART A) As half its initial value is u'=2u, then

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$dU = -\frac{2Gm^2}{R}$

$dKE = -dU$

Therefore replacing we have that,

$\frac{1}{2}mv^2 =\frac{Gm^2}{2R}$

Re-arrange to find v,

$v= \sqrt{\frac{Gm}{R}}$

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Therefore the velocity when the separation has decreased to one-half its initial value is 816m/s

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$2r = 2*10^3m$

Therefore

$dU = Gm^2(\frac{1}{R}-\frac{1}{2r})$

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7 0

3 years ago

A 0.405 kg mass is attached to a spring with a force constant of 26.3 N/m and released from rest a distance of 3.31 cm from the

miv72 [106K]

Answer:

0.231 m/s

Explanation:

m = mass attached to the spring = 0.405 kg

k = spring constant of spring = 26.3 N/m

x₀ = initial position = 3.31 cm = 0.0331 m

x = final position = (0.5) x₀ = (0.5) (0.0331) = 0.01655 m

v₀ = initial speed = 0 m/s

v = final speed = ?

Using conservation of energy

Initial kinetic energy + initial spring energy = Final kinetic energy + final spring energy

(0.5) m v₀² + (0.5) k x₀² = (0.5) m v² + (0.5) k x²

m v₀² + k x₀² = m v² + k x²

(0.405) (0)² + (26.3) (0.0331)² = (0.405) v² + (26.3) (0.01655)²

v = 0.231 m/s

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