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zmey [24]
3 years ago
5

Spongebob was trying to make Krabby Patties that weighed 12oz. He made 4 Krabby Patties. They all had the following weights: 12.

12oz; 11.9oz; 12.2oz; 12.1oz. Is this an example of Accuracy? Precision? Both? Neither?
Chemistry
1 answer:
Assoli18 [71]3 years ago
8 0

Answer:

Yes, the 4 Krabby patties are an example of high precision.

Explanation:

Precision is the closeness of the values ​​obtained by applying them to the same parameter. To calculate the precision, the closeness of each of the values ​​with the mean must be determined, all the values ​​will be taken by subtracting the mean and the values ​​will be taken into account to know which are the most accurate.

(12.12 + 11.9 + 12.2 + 12. 1) / 4 = 12.08

12.12 - 12.8 = 0.04

11.9 - 12.08 = - 0. 18

12.2 - 12.08 = 0.12

12.1 - 12.08 = 0.02

The most accurate precision is that of the fourth Krabby Pattie and the least precise is that of the second.

You might be interested in
B. For the following questions, use the reaction NO2(g) N2(g) + O2(g), with ΔH = –33.1 kJ/mol and ΔS= 63.02 J/(mol·K).
Troyanec [42]

Answer:

I. Kindly, see the attached image.

II. The reaction is exothermic.

III. - 51.88 kJ/mol.

IV. The reaction is spontaneous.

Explanation:

I. Draw a possible potential energy diagram of the reaction. Label the enthalpy of the reaction.

  • Since the sign of ΔH is negative, the reaction is exothermic reaction.

In an exothermic reaction, the energy of the reactants is higher than that of the products.

<u><em>Kindly see the attached image to show you the potential energy diagram of the reaction.</em></u>

     

<em>II. Is the reaction endothermic or exothermic? Explain your answer.</em>

  • The reaction is exothermic reaction.
  • The sign of ΔH indicates wither the reaction is endothermic or exothermic one:

If the sign is positive, the reaction is endothermic.

If the sign is negative, the reaction is exothermic.

Herein, <em>ΔH = - 33.1 kJ/mol, </em>so the reaction is exothermic.

<em>III. What is the Gibbs free energy of the reaction at 25°C? </em>

∵ ΔG = ΔH - TΔS.

Where, ΔG is the Gibbs free energy change (J/mol).

ΔH is the enthalpy change (ΔH = - 33.1 kJ/mol).

T is the temperature (T = 25°C + 273 = 298 K).

ΔS is the entorpy change (ΔS = 63.02 J/mol.K = 0.06302 J/mol.K).

<em>∴ ΔG = ΔH - TΔS</em> = (- 33.1 kJ/mol) - (298 K)(0.06302 J/mol.K) = <em>- 51.88 kJ/mol.</em>

IV. Is the reaction spontaneous or nonspontaneous at 25°C?

The sign of ΔG indicates the spontaneity of the reaction:

If ΔG < 0, the reaction is spontaneous.

If ΔG = 0, the reaction is at equilibrium.

If ΔG > 0, the reaction is nonspontaneous.

Herein, <em>ΔG = - 51.88 kJ/mol, </em>so the reaction is spontaneous.

7 0
3 years ago
metal weighing 6.98 g was heated to 91.29 °C and then put it into 114.84 mL of water (initially at 24.37 °C). The metal and wate
torisob [31]

Answer:

The specific heat of the metal is 10.93 J/g°C.

Explanation:

Given,

For Metal sample,

mass = 6.98 grams

T = 91.29°C

For Water sample,

volume = 114.84 mL

T = 24.37°C.

Final temperature of mixture = 33.54°C.

When the metal sample and water sample are mixed,

The addition of metal increases the temperature of the water, as the metal is at higher temperature, and the  addition of water decreases the temperature of metal. Therefore, heat lost by metal is equal to the heat gained by water.

Since, heat lost by metal is equal to the heat gained by water,

Qlost = Qgain

However,

Q = (mass) (ΔT) (Cp)

(mass) (ΔT) (Cp) = (mass) (ΔT) (Cp)

After mixing both samples, their temperature changes to 27°C.

It implies that

water sample temperature changed from  24.37°C to 33.54°C and metal sample temperature changed from 91.29°C to 33.54°C.

We have all values, but, here mass of water is not given. It can be found by using the formula

Density = Mass/Volume

Since, density of water = 1 g/mL

we get, Mass = 114.84 grams.

Since specific heat of water is 4.184 J/g°C.

Now substituting all values in (mass) (ΔT) (Cp) = (mass) (ΔT) (Cp)

(6.98)(91.29 - 33.54)(Cp) = (114.84)(33.54 - 24.37)(4.184)

solving, we get,

Cp = 10.93 J/g°C.

the specific heat of the metal is 10.93 J/g°C.

7 0
3 years ago
Splitting of a signal in a proton NMR spectrum tells us the number of chemically non-equivalent hydrogens in the immediate vicin
PtichkaEL [24]

Answer:

True

Explanation:

In a given molecule protons in the same chemical environment absorb at the same applied field strength; whereas protons with different chemical environments absorb at different applied field strengths.

A set of protons in the same chemical environment are said to be equivalent. Hence, the number of signals in the NMR spectrum tell us the number of sets of equivalent protons present in the molecule.

Splitting of a signal in a proton NMR spectrum tells us the number of chemically non-equivalent hydrogens in the immediate vicinity of the hydrogen giving the signal.

6 0
3 years ago
An atom of 132sn has a mass of 131. 917760 amu. mass of1h atom = 1. 007825 amu mass of a neutron = 1. 008665 amu. calculate the
Lelechka [254]

The mass defect in amu/atom is 11.928.

The mass defect is the discrepancy between the nucleus of an atom's anticipated mass and its actual mass. This discrepancy is due to the binding energy of a system, which might manifest as excess mass.

The nucleus must be robustly spherical as expected for a doubly magical nucleus because the stripped neutron fell into a distinct orbital shell above the closed inner shells of tin-132 after the researchers examined the energy and angular distribution of the particles.

Mass of atom = 131.917760 amu

Mass of proton = 1.007825 amu

Mass of neutron = 1.008665 amu

Sn atom has 50 protons and 69 neutrons.

Mass defect = Mp + Mn - MA

                    = 50 × 1.007825 + 69 × 1.008665 - 131.917760

                    = 50.39125 + 69.597885 - 131.917760

                    = 11.928 amu/atom

Therefore, the mass defect in amu/atom is 11.928.

Learn more about mass defects here:

brainly.com/question/11410788

#SPJ4

6 0
2 years ago
2. A 237 g piece of molybdenum, initially at 100.0 °C, was dropped into 244 g of
Sophie [7]

Answer:

\large\boxed{C = 0.270J/g\textdegree C}

Explanation:

1. Energy balance

By the first law of thermodynamics, considering the system is closed and isolated, the heat released by the 237 g piece of molybdenum equals the heat absorbed by the 244 g of water.

2. Heat equation

The heat released or absorbed by a substance is proportional to the product of the mass, the specific heat and the change in temperature

  • Q = m × C × ΔT

3. Heat released by the 237 g piece of molybdenum

At equilibrium:

  • Q₁ = 237 g × C × (100.0ºC - 15.3ºC)

4. Heat absorbed by the 244 g of water

At equilibrium:

  • Q₂ = 244 g × 4.184 J/gºC × (15.3ºC - 10.0ºC)

5. Solve for C from Q₁ = Q₂

  • 237 g × C × (100.0ºC - 15.3ºC) = 244 g × 4.184 J/gºC × (15.3ºC - 10.0ºC)

  • 20,073.9 × C = 5,410.7488 J/gºC

  • C = 0.2695 J/gºC

The result must be reported with 3 significant figures: C = 0.270 J/gºC.

7 0
3 years ago
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