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SOVA2 [1]
3 years ago
10

Lead(II) nitrate, Pb(NO3)2, and potassium iodide, KI net ionic equation:

Chemistry
1 answer:
MissTica3 years ago
7 0

Answer:

Pb²⁺ (aq) + 2I⁻ (aq) → PbI₂ (s)

General Formulas and Concepts:

  • Solubility Rules
  • Reaction Prediction

Explanation:

<u>Step 1: RxN</u>

Pb(NO₃)₂ (aq) + KI (aq) → PbI₂ (s) + KNO₃ (aq)

<u>Step 2: Balance RxN</u>

Pb(NO₃)₂ (aq) + 2KI (aq) → PbI₂ (s) + 2KNO₃ (aq)

<u>Step 3: Ionic Equations</u>

Total Ionic Equation:

Pb²⁺ (aq) + 2NO₃⁻ (aq) + 2K⁺ (aq) + 2I⁻ (aq) → PbI₂ (s) + 2K⁺ (aq) + 2NO₃⁻ (aq)

<em>Cancel out spectator ions.</em>

Net Ionic Equation:

Pb²⁺ (aq) + 2I⁻ (aq) → PbI₂ (s)

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