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3 years ago

Which of the following concepts is shared by quantum theory and the Bohr model?

Chemistry

1 answer:

klasskru [66]3 years ago

5 0

Electrons move about the nucleus in defined orbits.

Explanation:

The Bohr mode of the atom was established based on the quantum mechanics originally developed by Planck.

He suggested that the extranuclear part of the atom consists of electrons in specific spherical orbits around the nucleus. The orbits represents the principal energy levels.

The quantum theory was developed originally by Planck.

He suggested energy exists in form of packets and discrete amount and not in form of flow like waves.

The quantum theory and Bohr mode in this regard as they both agree that electrons and energy are both quantized.

Learn more:

Bohr model brainly.com/question/4986277

#learnwithBrainly

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A student used 1.168g of an unknown weak acid and titrated it against 28.75 mL of 0.105M NaOH to reach the equivalence point. Wh

Vaselesa [24]

Answer:

The molar mass of the unknown acid is 386.8 g/mol

Explanation:

Step 1: Data given

Mass of the weak acid = 1.168 grams

volume of NaOH = 28.75 mL = 0.02875 L

Molarity of NaOH = 0.105 M

Since we only know 1 equivalence point, we suppose the acid is monoprotic

Step 2: Calculate moles NaOH

Moles NaOH = molarity NaOH * volume NaOH

Moles NaOH = 0.105 M * 0.02875 L

Moles NaOH = 0.00302 moles

We need 0.00302 moles of weak acid to neutralize the NaOH

Step 3: Calculate molar mass of weak acid

Molar mass = mass / moles

Molar mass = 1.168 grams / 0.00302 moles

Molar mass = 386.8 g/mol

The molar mass of the unknown acid is 386.8 g/mol

3 0

3 years ago

Peter is 5 ft, 11 inches tall. Paul is 176 cm tall. Who is taller?

arlik [135]

Peter is taller, convert cm to in.

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3 years ago

Red #40 has an acute oral LD50 of roughly 5000 mg dye/1 kg body weight. This means if you had a mass of 1 kg, ingesting 5000 mg

FrozenT [24]

Answer:

350 g dye

0.705 mol

2.9 × 10⁴ L

Explanation:

The lethal dose 50 (LD50) for the dye is 5000 mg dye/ 1 kg body weight. The amount of dye that would be needed to reach the LD50 of a 70 kg person is:

70 kg body weight × (5000 mg dye/ 1 kg body weight) = 3.5 × 10⁵ mg dye = 350 g dye

The molar mass of the dye is 496.42 g/mol. The moles represented by 350 g are:

350 g × (1 mol / 496.42 g) = 0.705 mol

The concentration of Red #40 dye in a sports drink is around 12 mg/L. The volume of drink required to achieve this mass of the dye is:

3.5 × 10⁵ mg × (1 L / 12 mg) = 2.9 × 10⁴ L

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3 years ago

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geniusboy [140]

Answer:

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What would happen to a animal cell if it had n\an lysosome?

pantera1 [17]

Honestly I don't know

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