Ask question

Ask question

All categories

2 years ago

13

The door to the club house has an area of 1,792 square centimeters. If the length of the door is 56 centimeters. How wide is the

door ?

1 answer:

babymother [125]2 years ago

8 0

Answer:

The width of the door is 32 cm.

Explanation:

The formula for area is A = l*w

so the equation becomes:

1792 = 56*w

Divide both sides by 56 and you get

w = 32

You might be interested in

Which of the following equations is true

lukranit [14]

Its the last one because 10 times 1 is 10 and 0 plus 10 still gives you 10

6 0

2 years ago

Read 2 more answers

Josue went to his favorite donut shop with his friend. The donut shop was having a special. A dozen donuts was selling $11.76. H

yan [13]

Answer:

0.98 cents

Step-by-step explanation:

All you do to solve this is ou do 11.76 divided by 12

11.76 divided by 12 is actually just 98 cents (0.98)

8 0

2 years ago

Solve angle X to 1 dp

geniusboy [140]

Answer:

x ≈ 57.8°

Step-by-step explanation:

using the Sine rule in the triangle

$\frac{11}{sinx}$ = $\frac{8}{sin38}$ ( cross- multiply )

8 × sinx = 11 × sin38° ( divide both sides by 8 )

sinx = $\frac{11sin38}{8}$ , then

x = $sin^{-1}$ ( $\frac{11sin38}{8}$ ) ≈ 57.8° ( to 1 dec. place )

7 0

1 year ago

Explain why S = {(5, 4, -2), (-15, -12, 6), (10, 8, -4)} is NOT a basis for R^3 (1 point Sis linearly dependent and spans R3 S i

earnstyle [38]

$S$ would be a basis for $\mathbb R^3$ if

(1) the vectors in $S$ are independent, and

(2) the vectors span $\mathbb R^3$ .

Linear independence requires that $c_1=c_2=c_3=0$ is the only solution to

$c_1(5,4,-2)+c_2(-15,-12,6)+c_3(10,8,-4)=(0,0,0)$

These vectors are not linearly independent because if $c_1=3$ , $c_2=1$ , and $c_3=0$ , we have

$3(5,4,-2)+(-15,-12,6)=(15-15,12-12,-6+6)=(0,0,0)$

so $S$ is not a basis for $\mathbb R^3$ .

7 0

2 years ago

Which of the following is a true polynomial identity?

AlladinOne [14]

C or d i think is the correct answer

5 0

3 years ago