F(x)=-1/x
g(x)=√(3x-9)
Domain of (f/g)(x): ??
1We find out the domain of f(x):
f(x) is a rational function, therefore can take real values if the denominator is not ("0"), therefore the domain of f, will be all values excpet "0"
Domain of f: (-∞,0)U(0,+∞);
o
----------------------------------------------O-------------------------------------------
←-------- -∞ +∞ ----------→
g(x) is a radical square root function, therefore the radicand have to be greater than o equal to "0"
3x-9≥0
3x≥9
x≥3
3
.........................................................Ф--------------------------------
←--------- - ∞ +∞ -----------→
(f/g)(x) = (-1/x) / (√(3x-9)) is a rational function with a square root in the denominator,also the square root don´t take the value of "0";
Therefore:
3x-9>0
3x>9
x>3
The domain of the function (f/g)(x) only can take the values found in all three domains at once.
3
............................................................0---------------------------------
←--------- -∞ +∞-------------→
Answer: (3,+∞)
Answer:
Space junk is travelling so fast that a collision with an astronaut or a spacecraft could be disastrous.
Explanation:
Space junk orbits the Earth at speeds of about 28 000 km/h.
That's so fast that even an orbiting fleck of paint has enough kinetic energy to cause impact craters on the surface of a spacecraft. They are even more dangerous to an astronaut on a space walk.
Much of the space debris is larger and more dangerous than a fleck of paint.
One rough estimate of the amount of space debris is
<em> </em><u>Size</u><em> </em> <u>Number of objects</u>
< 1 cm 200 000 000
1 cm to 10 cm 700 000
> 10 cm 30 000
Satellites, etc. 18 000
The chances of collision are small, but any collision can be disastrous.
Answer:
Δ S = 26.2 J/K
Explanation:
The change in entropy can be calculated from the formula -
Δ S = m Cp ln ( T₂ / T₁ )
Where ,
Δ S = change in entropy
m = mass = 2.00 kg
Cp =specific heat of lead is 130 J / (kg ∙ K) .
T₂ = final temperature 10.0°C + 273 = 283 K
T₁ = initial temperature , 40.0°C + 273 = 313 K
Applying the above formula ,
The change in entropy is calculated as ,
ΔS = m Cp ln ( T₂ / T₁ ) = (2.00 )( 130 ) ln( 283 K / 313 K )
ΔS = 26.2 J/K
Answer:
A cuz a heterogeneous mixture is no uniform
