Answer:
When the electron changes levels, it decreases energy and the atom emits photons. The photon is emitted with the electron moving from a higher energy level to a lower energy level. The energy of the photon is the exact energy that is lost by the electron moving to its lower energy level.
Explanation:
Answer: C, B, A
Explanation:
C is the initial solution, because naoh has not been added yet
B is the midpoint of the titration. naoh has been added to the solution, but it has not fully reacted yet. You can tell that this one is the midpoint because there is still HF- in the diagram, which is not one of the products formed in the reaction.
A is the endpoint because the diagram shows that all products are fully formed. There is an increased amount of Na+ and H2O in the diagram and no HF- left.
PS. I tested this answer on the concentration of acetic acid post-lab (from mcgraw hill) earlier today and it said this was the right answer :) hope this helps
The iupac name is ethylene glycol
The phosphorylation of fructose 6-phosphate to fructose-1,6-bisphosphate is the committed step in glycolysis because. it is the rate-limiting step
<h3>What is
phosphorylation?</h3>
The first step in the metabolism of carbohydrates is frequently their phosphorylation. Because the phosphate group stops the molecules from migrating back across the transporter, phosphorylation enables cells to store carbohydrates. Glucose phosphorylation is a crucial step in the metabolism of sugar. In the first phase of glycolysis, D-glucose is converted to D-glucose-6-phosphate using the chemical equation D-glucose + ATP D-glucose-6-phosphate + ADP G° = 16.7 kJ/mol (° signifies measurement under standard conditions).
The rate-limiting stage in the liver's metabolism of glucose is the initial rate of phosphorylation of glucose (ATP-D-glucose 6-phosphotransferase) and non-specific hexokinase. Hepatic cells are freely permeable to glucose (ATP-D-hexose 6-phosphotransferase).
encouraging certain glucose transporters to translocate to the cell membrane.
To learn more about phosphorylation from the given link:
brainly.com/question/2138188
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