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irina1246 [14]
3 years ago
9

A 2.00 kg piece of lead at 40.0°C is placed in a very large quantity of water at 10.0°C,and thermal equilibrium is eventually re

ached. Calculate the entropy change of the leadthat occurs during this process.
Chemistry
1 answer:
sveticcg [70]3 years ago
6 0

Answer:

Δ S = 26.2 J/K

Explanation:

The change in entropy can be calculated from the formula  -

Δ S = m Cp ln ( T₂ / T₁ )

Where ,

Δ S = change in entropy

m = mass  = 2.00 kg

Cp =specific heat of lead is 130 J / (kg ∙ K) .

T₂ = final temperature  10.0°C + 273 = 283 K

T₁ = initial temperature ,  40.0°C + 273 = 313 K

Applying the above formula ,

The change in entropy is calculated as ,

ΔS = m Cp ln ( T₂ / T₁ )  = (2.00 )( 130 ) ln( 283 K / 313 K )

ΔS = 26.2 J/K

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2 points
erica [24]

9 grams of hydrogen gas (H2) will SC  Johnson need to react in order to make 1 bottle of Windex.

Explanation:

Balance equation for the formation of ammonia from H2 gas.

N2 + 3H2 ⇒ 2 NH_{3}

Given

mass of ammonia in 1 bottle of windex = 51 gram

atomic mass of ammonia 17.01 gram/mole

number of moles = \frac{mass}{atomic mass of 1 mole}

number of moles = \frac{51}{17.01}

                               = 3 moles of ammonia is formed.

in 1 bottle of windex there are 3 moles of ammonia 0r 51 grams of ammonia.

From the equation it can be found that:

3 moles of hydrogen reacted to form 2 moles of ammonia

so, x moles of hydrogen will react to form 3 moles of ammonia.

\frac{2}{3} = \frac{3}{x}

x = 4.5 moles of hydrogen will be required.

to convert moles into gram formula used:

mass = atomic mass x number of moles  (atomic mass of H2 is 2grams/mole)

        = 2 x 4.5

        = 9 grams of hydrogen.

7 0
3 years ago
Methane burns in the presence of oxygen to form carbon dioxide and water.
wlad13 [49]

Answer:

= 9.28 g CO₂

Explanation:

First write a balanced equation:

CH₄ + 2O₂ -> 2H₂O + CO₂

Convert the information to moles

7.50g CH₄ = 0.46875 mol CH₄

13.5g O₂ = 0.421875 mol O₂

Theoretical molar ratio CH₄:O₂ -> 1:2

Actual ratio is  0.46875 : 0.421875 ≈ 1:1

If all CH₄ is used up, there would need to be more O₂

So O₂ is the limiting reactant and we use this in our equation

Use molar ratio to find moles of CO₂

0.421875 mol O₂ * 1 mol CO₂/2 mol O₂=0.2109375 mol CO₂

Then convert to grams

0.2109375 mol CO₂ = 9.28114 g CO₂

round to 3 sig figs

= 9.28 g CO₂

5 0
3 years ago
Question 1 (1 point)
lutik1710 [3]

Answer:

Radiation

Explanation:

Thermal energy (heat) can be transferred between objects as long as there is a temperature difference between them. However, there needs to be some kind of medium transferring it. There are basically three ways in which the energy is transferred:

1. Conduction - transfer via the direct contact  

2. Convection - transfer via the circular movement of fluids or air caused by hotter layers moving upward and colder downwards.

3. Radiation - transfer via the waves from the invisible spectrum of electromagnetic radiation ( ultra-violet, infra-red...)

Frequency is not a type of energy transfer, but a number of times something is occurring in one second. When we say that the frequency is 200Hz it means that something is happening at a rate of 200 times in a second. It's most often used in describing oscillations.

6 0
3 years ago
Which two parts of an atom determine the atom's mass?
DENIUS [597]

the number of protons and the number of neutrons determine an element's mass number. :D

4 0
3 years ago
What is the molarity of a NaOH solution if 32.47 mL is required to titrate 0.6013 g of potassium hydrogen phthalate (C8H5O4K)
Artist 52 [7]

Answer:

0.0907 M

Explanation:

Before you can calculate the molarity, you need to convert grams to moles (via molar mass) and convert mL to L.

(Step 1)

Molar Mass (C₈H₅O₄K):

8(12.011 g/mol) + 5(1.008 g/mol) + 4(15.998 g/mol) + 39.098 g/mol

Molar Mass (C₈H₅O₄K): 204.218 g/mol

0.6013 g C₈H₅O₄K             1 mole
------------------------------  x  ------------------  =  0.00294 moles C₈H₅O₄K
                                          204.218 g

(Step 2)

1,000 mL = 1 L

32.47 mL              1 L
---------------  x  -----------------  =  0.03247 L
                        1,000 mL

(Step 3)

Molarity (M) = moles / volume (L)

Molarity = 0.00294 moles / 0.03247 L

Molarity = 0.0907 M

6 0
2 years ago
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