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irina1246 [14]
3 years ago
9

A 2.00 kg piece of lead at 40.0°C is placed in a very large quantity of water at 10.0°C,and thermal equilibrium is eventually re

ached. Calculate the entropy change of the leadthat occurs during this process.
Chemistry
1 answer:
sveticcg [70]3 years ago
6 0

Answer:

Δ S = 26.2 J/K

Explanation:

The change in entropy can be calculated from the formula  -

Δ S = m Cp ln ( T₂ / T₁ )

Where ,

Δ S = change in entropy

m = mass  = 2.00 kg

Cp =specific heat of lead is 130 J / (kg ∙ K) .

T₂ = final temperature  10.0°C + 273 = 283 K

T₁ = initial temperature ,  40.0°C + 273 = 313 K

Applying the above formula ,

The change in entropy is calculated as ,

ΔS = m Cp ln ( T₂ / T₁ )  = (2.00 )( 130 ) ln( 283 K / 313 K )

ΔS = 26.2 J/K

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Answer:

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Aspirin can be prepared from salicylic acid ( C 7 H 6 O 3 CX7HX6OX3), which has a molar mass of 138.12 g/mol, and acetic anhydri
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Answer: The theoretical yield of aspirin is 4.14 g

Explanation:

To calculate the moles :

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mass of acetic anhydride = density\times volume =1.082g/ml\times 3.71ml=4.01g

\text{Moles of acetic anhydride}=\frac{4.01g}{102.04g/mol}=0.039moles

C_9H_6O_3+C_4H_6O_3\rightarrow C_9H_8O_4+C_2H_3O_2  

According to stoichiometry :

1 mole of salycylic acid require 1 mole of acetic anhydride

Thus 0.023 moles of  salycylic acid require=\frac{1}{1}\times 0.023=0.023moles  of acetic anhydride

Thus salycylic acid is the limiting reagent as it limits the formation of product and acetic anhydride is the excess reagent.

As 1 mole of salycylic give = 1 mole of aspirin

Thus 0.023 moles of salycylic acid give =\frac{1}{1}\times 0.023=0.023moles  of aspirin

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Please help me with chemistry!
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Reacting bromide (Br₂) with sodium iodine (NaI) will produce sodium bromide (NaBr) and iodine (I₂).

To balance the equation the number of atoms of each element entering the  reaction have to be equal to the number of atoms of each element leaving the reaction, in order to conserve the mass.

Br₂ (l) + 2 NaI (s) → 2 NaBr (s) + I₂ (s)

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3 years ago
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