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blondinia [14]
3 years ago
12

A roller-coaster car rolls down a frictionless track, reaching speed v0 at the bottom. If you want the car to go twice as fast a

t the bottom, by what factor must you increase the height of the track
Physics
1 answer:
NeTakaya3 years ago
3 0

Answer:

h should become four times.

Explanation:

The speed at the bottom depends only on the vertical height difference from the top ... if there is no friction ... then the path you take from top to bottom doesn't matter in any way, only the difference in height between the two

mgh at top = 1/2 mv^2 at bottom, so that v=sqrt[2gh]

You see, the final velocity, v, depends on the square root of h, so double v, quadruple h, or four times higher

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Answer:

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An oil film with refractive index 1.48 and thickness 290 nm is floating on water and illuminated with white light at normal inci
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Answer:

572.3 nm

Explanation:

n_{oil} = refractive index of the oil film = 1.48

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2 n_{oil} t_{oil} = (m + 0.5) \lambda

For m = 0

2 (1.48) (290) = (0 + 0.5) \lambda

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For m = 1

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\lambda = 572.3 nm

For m = 2

2 (1.48) (290) = (2 + 0.5) \lambda

\lambda = 343.4 nm

Hence the dominant color wavelength is 572.3 nm

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